How High Pass Filters Work using a Resistor and Capacitor (RC)

I explain how high-pass RC filters work using the falstad circuit simulator and a circuit which is similar to the one used with the low pass filters in a previous video.
The simulations include the circuit diagram showing current flow, capacitor operation, time-domain voltage plots at various frequencies, and a frequency response plot.

Below is the text of the code I used in Falstad:

$ 1 0.000005 14.235633750745258 55 5 50 5e-11

v 176 256 176 80 0 2 85 5 0 0 0.5

r 176 80 336 80 0 187

c 336 80 336 256 0 0.000009999999999999999 -4.2244607677073445 0.001

w 176 256 336 256 0

o 0 16 0 x81016 20 0.2 0 14 2.5 0 1 3 0.05 0 2 3 0.05 0 1 3 0.05 0 2 3 0.05 0 2 3 0.05 0 1 3 0.05 0 2 3 0.05 0 1 3 0.05 0 2 3 0.05 0 1 0 2.5 0 1 3 0.05 0 2 0 2.5 0 2 3 0.05 0

38 2 F1 0 0.000001 0.000101 -1 Capacitance

[Fundalf_the_greyt]

Great explanation, thanks! I didn't realize that high pass and low pass is basically the same circuit, just measuring voltage on a different component

[ThevonMusic]

Nice tutorial overall, but there's two things I can't figure out. I understand the order of the resistor and capacitor changed gives us a lowpass filter. I can also understand how depending on the load time of the capacitor certain frequencies are cutoff more than others. But... What I don't understand is the flow of the signal. If I look at this square wave generator, I see the pulse going from the + side one half cycle and then from the minus side one half cycle. In my mind It's like the + part it goes through the resistor first, which then passes our output point and then fills up the capacitor. On the minus side the other way around, first capacitor. I know this doesn't make sense, because the result would be one half cycle lowpass one half cycle highpass if that makes sense. I just don't really understand the flow of the signal and also when the capacitor discharges. Does it discharge to our output signal? Is this also causing our delay/phase shift? Second thing I don't understand is the resistor switch to double peak (10V).

[احمدعبدالكريمعبدالامير]

hello sir,
first thank you very much for you're amazing explanation but i have a question. shouldn't the capacitor by connected directedly to the ac source ? and the resistor in parallel with the output?

[JohnnyMoniz]

Quick question:
First of all, fantastic video!
I’m curious if a capacitor alone would work as a high pass filter in an audio experiment. My understanding is that capacitors naturally want to filter out low frequency. If I wanted my guitar effect pedal to be quieter at 200hz and below, why is it that I can’t simply put a capacitor of a specific value in series right at the output? (Or can I?) or what is it about the relationship with the resistor that makes both parts mandatory?

[kkgt]

Great video, audio is a bit clanky and needs some fixing to be clear.

[mejiqal]

the resisitor is just constant suck in electrons and output them as