Group theory - SOLUTIONS to problem set 1 (SYMMETRY GROUPS)

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00:00 problem 1
08:08 problem 2
14:03 problem 3
24:27 problem 4
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Problems 1, 2, 3 were fun!

Problem 4 was hard in the beginning. Then I tried to understand the notation and wrote down the simpliest terms.
[ f ] (a) = f(a)
[ f ° g ] (a) = [ f ] ° g(a) = f(g(a)) means: first calculate function g of a and than calcualte f of g (that was calculated of a).
[ f ° g ° h ] (a) = [ f ° g ] ° h(a) = [ f ] ° g(h(a)) = f(g(h(a))) means: first calculate h of a, than calculate g of h (that was calculated of a) and than calculate f of g (that ...)

Now, it was fun, too.
[ { f ° g } ° h ] (a) = [ f ° g ] ° h(a) = [ f ] ° g(h(a)) = f(g(h(a)))
[ f ° { g ° h } ] (a) = [ f ] ° { g ° h } (a) = [ f ] ° g(h(a)) = f(g(h(a)))

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Thank you for taking the time to create these videos! I am the perfect audience for your videos.

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