Convergence of the Taylor Series of sin(x)

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At the beginning, when I wrote the Taylor series for sine, I wrote (-1)^(n+1) when it should have been (-1)^n

JCCCmath

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Thank you! This really cleared up a lot of things for me - i didn't really know what convergence meant after learning taylor polynomials and this makes it clear that it's concerned with whether the approximation eventually becomes identical to the function. I've subscribed and I hope you keep making math videos!

InspirationIsFree

Thank you for the video. I think there is a small mistake in the first formula though: it is "n" instead of "n+1" in the exponent of (-1). Best regards

lel

This is a great video and you are a great teacher.

izzygrandic

it is a very good explanation indeed, however it is too trivial. a more difficult problem could be used. thankss

barancel

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