How to find a TURNING POINT of a QUADRATIC | GCSE Maths 2023

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Homie you literally saved me a shit ton of time, even chatgpt couldnt do it for me lol. Thanks alot bro appreciate u

hammzasalman_

OMG GOD BLESS YOU OMGGGG I WASN'T UNDERSTANDING ANYTHING YOU SAVED ME THANK YOU THANK YOU 🩷🩷🩷🩷

callmehayu

-b/2a = x value of turning point
= -(10)/2(1) = -5
Plug -5 back into the quadratic to find y value
f(-5) = (-5)^2+10(-5)+24
= -1
Turning Point = (-5, -1)

r_xi

Bro you are actually so underrated thank you so much

alienlord

Bro thanks.. here is an easy way of doing it

a=1
b=10
c=24

Step 1.
p= -b/2a
p=-(10)/2(a)
p=-10/2
p=-5

Note: p is equals to the x coordinate .

Step 2:
q= 4(a) (c) - (b)²/ 4(a)
q=4(1) (24) - (10)²/ 4(1)
q= 96 - 100/ 4
q=-4/4
q= -1

(-5, -1)

Note: q is equals to the y coordinate.

Endguysplayz

Amazing 🥰 I'll understand, answer and pass my exams with flying colours in the same way Amen🙏

victoriangandu

Another way is using -b/2a = x or just turning the equation into the standard form and solving it

kelvincoemsfactory

Thanks so much, first day of geometry and reviewed from last year. Didn’t get any of it and now I do in 2 mins of trying thx so much.

fisherdude

Do -b/2a and plug the answer into the quadratic to get your y value and use the same x value

hugodelagarza

I have my baseline test for gcse recap tomorrow and I'm in yr12 I forgot about this and you saved me time and is very useful
Thank you

rjfuzoi

never have i understood math so quickly, thank yo broski 🫶

Doll

If the x was a number would u also divide the number by 2? Pls someone tell me I have my maths test tomorrow

LDNJinx

when we have a quadratic eqn with a negative coefficeint, does this still work as is or must we take the - sign in common and THEN carry the formula out?

crepfish