Singularities of Analytic Functions -- Complex Analysis 20

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The limit at 21:21 should be r->0, not r->infinity. Then M times a positive power of r (for negative n) goes to zero as required.

ingobojak
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Nitpick about 22:30 (the second of the three equivalent statements): g isn't defined at z_0. Shouldn't we instead say that g has a removable singularity at z_0?

Jeff_Saunders
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I just wanted to say that these course videos have been awesome. I haven't been able to keep up super well with the material during my term, but now that the summer is rolling around...

:)

TheEpicProOfMinecraf
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21:40 r is less than R, so it shouldn't go to infinity. For n<0 the term M/r^n doesn't converge to 0 in my opinion when r tends to infinity 🤔

thomashoffmann
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I hope we have a video on common meromorphic function examples. Not like exponential or trig functions, but weird functions like the Gamma function

JM-usfr
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I'm a bit confused on the definition of isolated singularity. Wouldn't that make any point in an analytic function be an isolated singularity? Because, if a function is analytic and we just consider the point z_0 ( even if f is analytic on z_0), we can definitely find a punctured disk where f is also analytic. Or am I missing something? Does the fact that we are considering a punctured disk mean that we don't really care whether f is analytic on z_0 or not?

jimallysonnevado
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Around 28:00
The preconditions of the theorem is maybe not enough. It has to be an isolated singularity which is not removable. Otherwise the limit doesn't need to be infinity (?)

thomashoffmann
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30:32 It looks like Michael assumed that 1/|f(z)| has a isolated zero at z_0?

broccoloodle
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Thank you for the awesome lessons/content!

Can we also expect to see a course on differential geometry?
I know I'd love to.
:)

Invalid
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Convergence is dual to divergence.
Poles (eigenvalues) are dual to zeroes -- optimized control theory.
Analytic (mathematics) is dual to synthetic (physics) -- Immanuel Kant.
"Always two there are" -- Yoda.

hyperduality