Motion in a Plane: Projectile Motion Class 11 |One Shot| JEE 2024 | IIT JEE |Vinay Sir @JEEVedantu ​

Watch this amazing session on Motion in 2D JEE. Here Vinay sir is going to cover the Complete Motion in 2D Class 11 One-Shot for the JEE 2024 Preparation. This session will be very helpful for the students who are preparing for JEE 2024 Exams. So, watch the complete video, and let's get a better understanding of the Motion in 2D JEE Physics.

➡️ Avail all Exciting Vedantu Courses 🔥 by clicking on the links below 🤑

📢 𝐀𝐥𝐥 𝐏𝐂𝐌 𝐒𝐞𝐬𝐬𝐢𝐨𝐧𝐬 𝐟𝐨𝐫 𝐉𝐄𝐄 𝐏𝐫𝐞𝐩𝐚𝐫𝐚𝐭𝐢𝐨𝐧 𝐚𝐭 𝐎𝐧𝐞 𝐏𝐥𝐚𝐜𝐞 [𝐀𝐥𝐥 𝐢𝐧 𝐎𝐧𝐞 𝐃𝐨𝐜𝐮𝐦𝐞𝐧𝐭🤩]

➡️ Avail all Exciting Vedantu Courses 🔥 by clicking on the links below 🤑

#MotionIn2DJEE #JEE2024 #VinaySirVedantu #JEEMain2024 #VedantuJEE #JEEDroppers #MilkeMachateHain #JEE #StayHomeWithMe #LearningWontStop #DailyLiveJEEClass #OnlineClassesforJEE

🚀 **IMPORTANT PLAYLISTS & SESSIONS:**

Sounds Amazing?

---------------------------------

Thank you so much guys for watching the video. We hope, this session will help you get a better understanding of the topic. We would love to get your feedback. Please do comment below in the comment section.

[adityaswaroop]

method to find range(max) in inclined plane is as follows:-
1) calculate the range using the formula [R = / gcos^2(alpha)]
2) On simplifying, we will get
3) now we can conclude that Range(max) is at sin(2theta+alpha) is max = sin 90
therefore, 2theta+alpha = pie/2 => theta = pie/4 - alpha/2
4) on substituting theta as pie/4-alpha/2, we get [R=u^2{1-sin alpha}/g cos ^2alpha]
which on further simplification gives,
[R=u^2/g(1+sin alpha)] (on rationalisation)

[AAA-qxnb]

44:40 IMP rember concept
1:03:30 IMP Que with an imp concept
1:07:00 IMP QUE
1:11:30 NEw way to see at above IMP QUE
1:14:00 Limitation concept of above IMP Que

[amitayush]

1:02:15
Ans
(i) Hmax = 3.2m
(ii) Range = 2*6*8/g = 9.6m
(iii) Time of flight = 1.6s

[Dynamic.g]

1:56:29
Time: 3sec
Height: 9m
Range: 21m

[varungundu]

Tf-0.16 sec
R-9.6m
Max h -3.2 m
Is it right??

[JatanKumar]

At 1:56:29 Those who are getting 12m as range they are actually taking acc. along y-axis... Take it along x-axis and you will range 21m.

[SKPGenius]

You are only a person who wants really to help us, , and VEDANTU is super one of all live batches.
VERY VERY THANKS to your hard work ( Help) for us.

[jayantadutta]

I can't explain by words that how nicely you have explained Sir. Thank you very very very much....

[stepfromheaven]

The best physics tutor i have ever seen.... ❤

[getyourcode]

completed successfully 💖 . Thank you sir

[DakshUpasani-nl]

1:00:23
Hmax = 5m
Time of flight = 2secs
Range = 48/5 m

[michaelrinal]

Sir you are next gen teachers. Awesome Sir 😎

[anweshapattanaik]

Thank you sir ... concept is now concentrated

[knowledgecurve]

Gajb ka revision lecture hai, Pura chapter mind me set ho gya🙏❤️❤️

[anasnoobnoobisanas]

If ay is -gcosB so how t is usina/ay 1:47:05

[haria]

Sir your teaching Is nice
Please teacher is in English

[princeshukla]

Sir aap derivation bhi krate ho bcz mai school level ki preparation kr raha hu pls reply sir

[DeepaV-oerq]

I have great luck, i found this video right after my exam.

[san_shaurya]

One of the best vdo with full concept thanks sir

[astronaut]

1:56:34
time = 3 sec
height = 9m
rrange = 45m