Motion in a Plane Class 11 | Projectile Motion | kinematics 2d class 11 NEET Physics | Abhishek Sir

Learn about motion in a plane and kinematics 2D in Class 11 with Abhishek Sir. Perfect for NEET Physics preparation on Vedantu's neetx platform!
Motion in a Plane Class 11 | Projectile Motion | kinematics 2d class 11 NEET Physics | Abhishek Sir

0:00 Motion in a Plane
4:15 What is 2D Motion ?
8:35 Projectile Motion | Height | Time Of Flight | Range
45:28 Practice Problem
1:11:39 NEET Problems

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[.oindrilamandal]

I have been following you since class 10 sir. You are my motivation. I think I manifested you teaching in 11 and 12. Thank you so much for helping us out and for all your hardwork.

[AaravAzad-cqsn]

come to think of it people like galileo and newton derived such equations and formulas literally 200 years before without any technology pure observations, such smart and genius mind litreally leaves me amazed fr beauty of physics

[dilarabarbhuiya]

Sir itna mehnat kar rahe ho par fir bhi views nahi aarha hai ..

[rithikiitiitian]

Sir please continue all lectures....❤️😭 Sir apke upar hi dependent ha

[ZikraKhan]

Finallyy! Intezar khatam, EXCITED 😌❤️✨

[prashansaMishra-penc]

Sir Maine first time aapki video dekhii haii aur itne teacher kii iss chapter ki video dekhii pr samjh nhi aayi aapne itne axe se sab clear krdiyaa thankyu so much sir✨✨

[gameonhighlights.]

Sir Maine apse class 10 me padha tha mere science me bahut acche marks aaye ab mujhe class 11 me physics samajh nahi aa rahi thi lekin ab aap padhane lage to mujhe physics samajh aane lagi hai thankyou so much sir ❤❤❤ for helping me to study without costly

[HarjinderK-cf]

Sir tomorrow is my exam and I am watching your videos today❤❤❤❤❤

[devendra-kumar]

HW answer

Given,
H=25m, u=40m/s

Let, g=10m/s², theta = x

H=u²sin²x/2g
25 = (40)² sin²x / 2(10)
25 = 1600 sin²x / 20
25 = 80 sin²x ( since, 1600/20 = 80)
sin²x = 25/80
sin²x = 5/16
sin x = √(5/16)
sin x = √5/4
x = sin inverse (√5/4)
x ≈ 0.559 ≈ 34°

Now, range is :
R = u² sin2x/g
R = (40)² sin(2×34) / 10
R = 1600 sin 68° / 10
R = 160 × 0.9271
R = 148.3m

Sir is the answer correct?

[SwatiSingh-]

Following u from 9th and again decision i ever made😅...jithe vi tu chalna ae mai tere piche piche chalna🌸🫣
Thenkeww sir for always being there with us💗

[LifeofanAakashian]

Sir I got 91% in boards or apke vedantu 9 nd 10 channel s mene prep ki thi❤❤ tq 💗

[sakshisakshi]

Sir I have seen many teachers but they don’t explain this way, you made it so easy to understand and lovely session. You are made for. teaching sir 🎉❤❤❤❤

[Dishad.]

Sir kya me sirf board level ke liye bhi ise pad sakta hu??? Kya ncert ke sare topics hai isme ???

[RAVIPRAKASHYADAV-qv]

DOUBT
Question 4, level 2: if maximum velocity is zero for y direction how come it is not 0 for velocity in x direction? At the maximum height the velocity is 0 for all direction no?

[RounaqNehra-vcns]

Thanks sir purre YouTube PE sabse acchi explanation hai aapki

[sadhanasharma]

Sir Question practice on vectors please.

[princeyadav.]

Is this sufficient for school level exams ?

[Chikri...chuperi]

Sir aap ekdam simple way me pura basic se smjha dete hai🎀💗

[pavanimalkapuram]

Sir, i think you made a mistake in solving the NEET–2022 question at 1:30:10, you had to take u cos theta as vertical component of velocity becomes zero at max height, hence answer is 10 (cos 60°) = 5 m/s 😊