PreCalculus - Trigonometry: Trig Identities (36 of 57) Product to Sum Formula 2

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In this video I will prove cosAcosB=(1/2)[cos(A+B)+cos(A-B)] and sinAsinB=1/2)[cos(A+B)-cos(A-B)].
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I am horrible with trig identities, but you really saved me there. Very clear and easy to understand, thank you so much!!

sdgray
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Is the negative sign not supposed to change also when you divide cos(A+B)-cos(A-B) by 2? I mean are all the signs not supposed to change giving cos(A-B)+cos(A+B)? Why is the negative sign(-) in between cos(A+B) and cos(A-B) remain thesame after dividing by negative two(-2)?

ChrisnaldoFabrolo
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That identity cosacosb can be proved using complex numbers?

cesarluisnava