Friction Class 11 | One Shot | JEE 2024 | IIT JEE | Vinay Shur Sir @JEEVedantu​

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Thank you so much guys for watching the video. We hope, this session will help you get a better understanding of the topic. We would love to get your feedback. Please do comment below in the comment section.
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Hw answer at t= 1:38:30
Distance -D on the plane ( from ground we can use trigno)
D= Vo²/2g(Sin theta+ u cos theta)
With thanks n regards
Shivansh🙏🏻

shivanshjee
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1:38:30
Is the block is retarding, it's deceleration due to friction is given by
a = gsintheta - ųgcostheta
v²-u²=2as
Vo² = 2as
Vo² = 2(gsintheta - ųgcostheta)s
Vo² = 2g(sintheta - ųcostheta)s
s = Vo²/2g(sintheta - ųcostheta)

anirudhghatty
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H.W. answer (1:38:28)
Distance when object stops...
d = (Vo)²/2g(Sin theta - μ cos theta)
👍
(Hint: find retardation due to friction by formula “a= g sin theta - μ g cos theta”)
Then, put values in 3rd equation of will get the answer!

rudrakshgarg
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Sir at 40:22 how you directly made it equal to zero Please answer

Nova-ys
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Thank you sir for your awesome teaching without wasting in reading chats and wasting time which other channels do ✌

apurbarakshit
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Sir please work energy and power bhi kara dijyr 🙏🙏🙏🙏🙏

subhanshuverma
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sir at 31:15 if force is greater than 6 then friction 5.4 hoga na aapne 5.6 likha hai

himanshimathur
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Thank you so much sir you are one of the best. I missed the friction lectures from my college and here you made me understand it perfectly within just 2 hours

rushilrudra
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really a helpful session and increasable confidece in friction chap..

SKPGenius
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Sir make a playlist for jee 2024 11th please sir aap bahut achha banate ho but playlist banao aasani hogi

vijaypatil
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Legend are watching before 1 day of exam ❤

karannnn_
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Sir plz bring practice sessions of class 11 12 th

adityaupadyay
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Sir please do some problems for jee advanced 2024

raghav
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Cohesive forces strong, so same smooth srgaces also gives friction

prakashchandradosi
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Sir mai pehli bar kr rha hu 11 kya mai yha se kr lu kyunki 11 me nhi padha tha shi se😢 for jee mains 2nd attempt.

fantasyfriendsiddhartha.
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Sir, kinetic friction how u got 5.6 newton which remains vonstNt

deepashriyadappnavar
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Yes sir yes sir yes sir yes sir yes sir😂😂😂

prateekpoonia
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Sir you didn't tell angle of friction

GurupadayyaHiremath-sdjf