Separable Differential Equations (Differential Equations 12)

How to solve Separable Differential Equations by Separation of Variables. Lots of examples!!

[johnorangez]

This guy is my definition of success... smart, fit, and loves what his doing!!

[ThatDereKid]

"...Partial fractions. Let's take a moment to review that." THANK YOU! I cannot thank you enough for reviewing things. So many teachers are prideful and pretend that students shouldn't have to review or that it isn't worth class time. I'm taking Diff EQ this semester at a top 50 university and that is what my teacher did about partial fractions. Meanwhile you walk through an example that is properly explained and point students toward a full Calc 2 video (that you MADE) in case the singled out examples here makes them realize that they really need to review the concept in full. Your teaching is proof that many others who teach with a false style of "practical arrogance" simply have no excuse. Thanks.

[hslowmarch]

Sometimes I have to watch his video at least twice because of his biceps

First time: His muscle..
Second time: very detailed explanation.. Got it!!

[ElNietoPR]

I no longer take math, but I still come here to like your videos. Thank you!

[hollybee]

"you're solving differential equations, pretty cool. I'm proud of you, man" My life force returned at this very moment

[E.C.REDEEM]

Professor Leonard said, "Im proud of you, you're solving differential equations, that's pretty cool". Thank you professor Leonard, you have helped me through my time at community college and have helped me transfer to a 4 year university, Thank you!

[vespermwin-banzora]

I really enjoy watching the works of Professor Leonard. He is indeed a true mathematics teacher who takes his time to present his content. I admire him so much. Thank You Prof.

[pungency]

can we have a video of your gym routine? biceps the size of boston right there

[zafarkhan]

We as students could never thank you enough for what remarkable contribution you have in building our concepts firmly.You have definitely helped hundreds if not thousands of students. I owe you my academic success prof leonard!!!!

[hourz]

Man its crazy to me I was watching his pre algebra course in 2020 at 30 years old with basically a 4th grade math level which was stated on my records on my HS graduation 12 years ago.
now I'm in calculus 2 about to graduate from my community college after this fall semester.

I hope I don't hit the celling with calculus 2. however, what I learned about myself I am not afraid of failure and persist until I make it.

Thank you professor Leonard!

[photon]

dude. You have no idea how USEFUL your videos are to me!!! I wish i had discovered you before my exams...

[sydneybrown]

Thank you for always explaining the steps in integration, had a problem with partial fractions in lecture today and the professor didn't go through the steps at all and no one remembered how to do them. Your videos saved me in multivariable calculus, and I look forward to learning with you in differential equations as well!

[krystygaytan]

the pep talk he gave somewhere in here brought the sparkle back into my eye. thanks professor.

[LmaEx]

I finally passed calculus 2 now i can watch this 🤣💔

[ricardosaldana]

Let's all share his channel and get the Prof. To 300k subs by the end of the week!!! He's almost there. Hit up all the math blogs!!!!

[HS-yxby]

You are seriously my saving grace. Thank you so much for these! The only reason I passed calculus 3 and now calculus 4 is because of you. Wishing you all the best!

[actuary]

Are you planning on covering partial differential equations in this course? Thank you for all of your efforts.

[giabachng]

Thank you, Professor. I think other people already said how much we appreciate these lectures.

[frustrated]

It might be late or maybe some people have already commented this, but you can actually *set the arbitrary constant 'c'* as *ln|c|* and combine it with the term that uses 'ln', too.. for example, in the 1st problem, ln|y|=-x^2 + c1 can be written as ln|y| = -x^2 + ln|c1|, then ln|y|-ln|c| = -x^2, to ln|y/c| = -x^2. Putting 'e' on both sides will result into e^ln|y/c| or y/c = e^(-x^2). You will then finish with the solution which is *y=ce^(-x^2)* without going through an additional process..

[DaHoKilla]

Leonard you are the goat im so glad to have found your channel, saved me in calc 2, 3, and now DE!!