Compton Scattering

MIT 8.04 Quantum Physics I, Spring 2016
Instructor: Barton Zwiebach

License: Creative Commons BY-NC-SA

[marialiyubman]

Words can’t express my gratitude to whoever made these courses available to the public for free. Thank you. ❤️

[mjackstewart]

I think it’s adorable how he says:

Photons: phot’ns
Electrons: electr’ns

[CARLOSSAA-yf]

absolutely flawless professor Zwiebach!

[aravindgundakaram]

The way they ended this video in mystery makes the viewer want to continue studying the next video 😂

[skm]

hello from India, very helpful video lecture, made the topic crystal clear
this what a perfect professor is!! thanks a lot MIT for this open course

[nthtell]

Wow he made equations look simple by explaining everything simply like it's natural things to happen.

[davehses]

Fantastic lectures. No wonder MIT is world's number 1.

[oscaraguilar]

Llevo viendo estos videos toda la semana. joder que guapo es tener plata para pagarte un buen maestro

[brendastephanie]

I can't believe it, MIT is cliffhanger us with PHYSICS CLASSES

[isatousarr]

Compton scattering is a fascinating phenomenon that illustrates the dual nature of light, behaving both as a wave and as a particle. It occurs when a photon collides with a charged particle, typically an electron, resulting in a transfer of energy and momentum. This interaction leads to a longer wavelength of the scattered photon, which is a clear demonstration of the particle-like behavior of light. Compton scattering not only plays a vital role in our understanding of quantum mechanics but also has practical applications in various fields, such as astrophysics, medical imaging, and radiation therapy. The study of this effect has significantly contributed to the development of quantum theory and our understanding of electromagnetic radiation.

[jimshilleto]

By diagonalizing the matrix M = (cos alpha, sin alpha; cos beta, sin beta)^T, in the new basis B ={v1, v2}, we see that if the beam splitter's lines are set to v1 and v2, the eigenvectors of M with two distinct eigenvalues a1 and a2, then the phase factors become simply a1*v1 and a2* v2. So the calculations become very simple when the light rays travel along lines v1 and v2 instead of 45 degrees up and 45 degrees down.

[stijndhondt]

Boy if there ever was a cliffhanger... It does seem L3.4 doesn't continue where this one stops. Anyone have an explanation to why the first bump is there?

[oggythebug]

Hello very interesting lecture it is exactly what i studied here in my country in france, in 1980 on my last school year before going for my first year at the university, we studied everything shown here, photoelectric effect and compton scatering plus the special relativity including all the equations writen on the blackboard, we even had to learn the demonstration of the final compton scatering formula i still have this in my book that i kept all these years, i think the level was high in those years, we were only 17 years old. best regards

[jacobvandijk]

Compton Scattering reminds me of the way Rutherford detected the nucleus of an atom!

[johnbruhling]

My best guess for the reading of λi is that they are the reflected x-ray particles that did not interact with a virtually free electron. The prepared crystalline structure of the metal might provide places where the x-ray particle can oscillate on the surface without resistance and also without an electron in affecting proximity and then could be reflected by a following x-ray particle with trivial energy loss.

[nibussss]

I also think photons are just particles that look like a wave when it bounces off other particles. I though it was my idea....last time I checked it was considered wave/particle duality...

[Bai_Su_Zhen]

Now I'm curious. Why is there the other peak? :D

[ryanyi]

In the photoelectric effect, we know that the material absorbs light by quanta. But in Compton scattering, the electrons partially *absorbs*(collide) the energy of high energy photon. So are the two (the photoelectric effect and Compton scattering) contradictory?

[nibussss]

Photon must have repelling with some other X particle which makes high energy photons bounce off a lot....

[shivamkakkar]

how can a photon loses its energy?
As it has packets of energy how can it be lost after hitting to electron.There is something more which is till Now unnoticable which changes some of photon's property.