Compton Scattering: Explanation and Derivation

In physics, it often helps to start with a picture.

NOTE: There is a mistake at 2:26! The energy of the electron after collision should include the electron's initial energy. In algebraic terms, E_e^2 = E_0^2 + (p_e⋅c)^2. You should get an (m_0⋅c^2)^2 term on both sides of the equation, which cancels out.

0:00 Intro
0:10 Compton Scattering, a Doodle
0:55 ∆λ and θ
1:35 Conservation of Energy
2:40 Conservation of Momentum
4:45 Final Equation

Sources:
-Carroll, Bradley W., and Ostlie, Dale A.. An Introduction to Modern Astrophysics. United Kingdom, Cambridge University Press, 2017.
-University Physics III - Optics and Modern Physics (OpenStax), The Compton Effect

Intro and Outro:
"Astronaut in the Ocean" by Masked Wolf, beats by FaMusic

[Science_-]

in about 2:26, shouldn't there be a (MoC)^2 term?
sorry i am bad at algebra

[RAHATIMRAN-wt]

Appreciable. I'm a UG at IIT Bh. and would suggest everyone to watch it. Why ? Cause shortest duration, precise and accurately to the topic points.

[discopotato]

Since I found Astro's explanation a bit confusing, I would like to add some clarification about the tiny error at around 2:26: The energy of the electron after scattering, according to relativistic mechanics would actually be E_e = sqrt[(m0^2)c^4 + (p_e*c)^2]. This would also give you the motivation behind squaring all the terms in the Energy Equation AND as to why we divided everything by c^2, while getting rid of the extra (m_0*c^2)^2 arising from the error.

In any case, keep up the great content AstroNaught!! It was a nice video.

[krypto]

Hello the class of Parker Harrison Stonier currently in the ib program in France

[KaasyapVepa]

Lot of errors at 2:26 and at 4:15 what happened to the (p-p') that was in multiplication of m_o C?