Conditional Expextation-II

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The best from the best. Thank you for this lecture.

kudakwashejisinau
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This lecture and the one before it were very helpful. I’m trying to learn this stuff in the foundations of modern probability, but it’s all a bit too dense.

robvdm
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What is going on at 8:15? What's meant by integrating (X, Y) w.r.t P? Is that suppose to be a product (i.e. X*Y)? And how did that result even come about?

harisfawad
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At 8.25, is it int of Y with respect to Q?

bhavinmoriya
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Thanks for sharing thoses classes. Although many details are lacking, it is nice for getting acquainted with. Greetings from Brazil!

Dion
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Thank You for the lecture really helped alot.

zafarkhan
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At 23:02 shouldn't it be as follows:
E[X.Y|G] = X.E[Y|G] instead of X.E[X|G]?

charukapila