Special Programs in C − Adding Two Numbers Without Using The Plus Operator

C Programming & Data Structures: Special C Programs − Adding Two Numbers Without Using The Plus Operator.
Topics discussed:
1) Adding two numbers using the increment and decrement operators.

Music:
Axol x Alex Skrindo - You [NCS Release]

#CProgrammingByNeso #CProgramming #PlusOperator

That's just weird image source:

[hetaeramancer]

I'm literally becoming smarter and more clever in coding because of Neso. Thank you so much Neso!

[simasaha]

We can also run a for loop where I<=y and which will return x++. So the loop will run until Y. So it's basically x+y.

[devukun]

I WAS able to solve the problem without actually looking at the solution, I did it using for loop instead,
thank you neso :)

[roshanmhatre]

This Can be done in few steps easily
Printf("The sum is %d", a-(-b));
Considering two no.s are a and b

[eslamosamasaadfathallah]

in my opinion, increment and decrement are basically like add and subtract operators and there is other way without using them and can be used for negative and positive numbers.

[codebits]

there is another method to solve this for positive as well as negative integer value
#include <stdio.h>
int main( )
{ int a, b, i;
printf("enter two number for addition\n");
scanf("%d%d", &a, &b);
for(i=1;i<=b;i++)
a++;
printf("sum of two number a and b is=%d", a);
return 0;
}

[prathamchhajed]

I've write the code just by seeing question ❓
All thanks to u bhaiya.

[anuraggupta]

Real question would be add 2 no. without using any operator.
None of operator present in operator chart is allowed

[itihas_verma]

Home work problem needs a minor changes: use signed int....instead of int.

int main(){


signed int a, b;
printf("Enter num n...");
scanf("%d%d", &a, &b);

while(b!=0){
a++;
b--;
}
printf("Sum : %d", a);
return 0;
}

[laskdjf]

I just did this:
int main()
{
int b, a;
printf("Enter two numbers to add together\n");
scanf("%d %d", &a, &b);

for (int i = 0; i < b; i++)
{
a++;
}
printf("%d", a);

}

[davisochieng]

I was thinking of x - ( -y ).
You make y to be negative then, subtract it from x

Example :
4 + 3 => 4 - ( -3 ) => 7

[desuchan]

my answer before the example after seeing the algorithm

int x=3, y=4;

for (x != 0; y != 0; ++x){
y--;
}

printf("%d", x);

[RAVITEJAP-ssrl]

include<stdio.h>

int main()
{
int i, x, y;
printf("Enter any two numbers to add: ");
scanf("%d%d", &x, &y);
if(y>0)
for(i=y;i!=0;i--)
x++;
else
for(i=y;i!=0;i++)
x--;
printf("Sum=%d", x);
return 0;
}



Tried by own and got the result🤩

[vinayakbhandage]

int a = -13, b = 2, neg = 0, val = 0;

if(a < 0) {
neg = a;
val = b;
}
else {
neg = b;
val = a;
}
while(neg != 0) {
val--;
neg++;
}

System.out.println(val);

This is for Addition with a negative value (JAVA).

[kuntellashanker]

Mind blowing explanation, keep uploading videos

[OvaseRashid]

Increment includes '+' ... So i used maths (a+b) = (a^2 - b^2)/(a-b) ...

[DSAbyraj]

Sir the video is nice.... But we are using + operater while incrementing it 😂😂😂

[prashanthchary]

For Negative Numbers hope the following code works :

#include<stdio.h>

int main()
{
int x, y;

printf("Enter the two Numbers you want to add\n");
scanf("%d %d", &x, &y);

if(x<0)
{
while(x!=0)
{
x++;
y--;
}
}
else
{
while(x!=0)
{
x--;
y++;
}
}

printf("Sum of two values is %d", y);
}


Sir can you please comment on this.

[BiswajitDas-jdji]

It can be solved simply using pointer, ++ and -- doesn't require 😊

[NikhilKumar-evml]

this program can use for addition of negative integers also