Special Programs in C − Binary to Decimal Conversion

C Programming & Data Structures: C Program For Binary to Decimal Conversion.
Topics discussed:
1) Binary to decimal conversion.
2) C program to convert binary number to its decimal equivalent.

Music:
Axol x Alex Skrindo - You [NCS Release]

#CProgrammingByNeso #CProgramming #BinaryToDecimalProgram

[itsbayahmed]

Here is another solution to this problem:

#include <stdio.h>

#include <math.h>

int main()
{
long long int number, num, result, n;

printf("Please Enter the Binary number: ");
scanf("%lld", &number);
result = 0;
n =0;
num = number;
while(num != 0)
{
result = result + (num % 10) * pow(2, n) ;
n++;
num = num / 10;
}
printf("%lld in decimal is %lld", number, result);
return (0);
}

[-HarishkumarG]

Idk how am I going to survive in IT field 😭

[sunnygomes]

Best channel for computer science students so far. Thanks for making such great contents.

[boblopez]

I did this program using shift left operator(<<), you can change the line ( decimal = decimal + rem*weight ;) with ( decimal= decimal + rem<<weight ;) and remove (weight = weight *2 ; ) and initialize weight with zero and it'll give you the same output, cuz shifting left is equal to multiplying with 2^weight

[madhavikatta]

Thank you so much
Sir one day I will be in the good position definitely on that day I will sponsor huge amount money to our channel

[mayankjadhav]

Thank you so much sir...today i understood the program and Sir please post binary to octal and hexadecimal too...

[Obama]

Great lecture. Many ways this can be done (including using the math.h library and utilizing the pow() function) but the previous person that taught me this didn't explain why we were doing the modulus and division in a clear way. You, however, did. Thanks!

[roshnimishra]

nice one
made the concept very clear
very helpful

[aakashmudigonda]

if anyone of you guys, didn't understand the above code, this my own code, which I made from a simpler logic....

#include <stdio.h>
#include <math.h>
int main(void) {
// example : convert 1 0 0 1 to decimal
// [1]*2^(3)+ [0]*2^(2)+ [0]*2^(1) + [1]*2^(0)
printf("enter a binary number : ");
int n;
scanf("%d", &n);
int temp = n;
int rem = 0;
int result = 0;
int count = 0;
int last_num= 0;
while (temp!=0) {
temp = temp/10;
count++;
}
temp = n;
for (int i = 0; i<count; i++) {
rem = temp%10;
last_num = rem * pow(2, i);
result = result+last_num;
temp = temp/10;
}
printf("%d is the required decimal number.", result);
return 0;
}

if you have any doubts go ahead and ask!

[ashokkumark]

We store hex value starts with 0x, and octal starts with 0 and decimal as it is in the integer type..
How do we store a binary number in the integer type??
Here why do we convert a decimal number to decimal again??
Where actually is it useful??
Can someone please explain??

[nikhilsingh]

nice lecture I got a hint for the CodeChef challenge thanks

[zoreladreanrivera]

#include <stdio.h>
#include <math.h>

int main ( void ) {

int binary;

printf ( "Enter binary number: " );
scanf ( "%d", &binary );

int counter1 = 0;
int A = binary;

while ( A != 0 ) {
A /= 10;
counter1++;
}

int remainder = 0;
int power = 0;
int sum = 0;
for ( int counter2 = 0; counter2 < counter1; counter2++ ) {
remainder = binary % 10;
power = ( pow ( ( remainder * 2 ), counter2 ) ) * remainder ;
sum += power;
binary /= 10;
}
printf ( "Decimal Equivalent = %d", sum );

return 0;
}

[Deepthi_Chowdary]

Sir u make more series on only focusing on problem..

[dambro]

i did it using biwise operators! it worked! ig
int bin_dec()
{
int bin, dec;
scanf("%d", &bin);
for (int shift; bin!=0; shift++)
{
int r = bin%10;
dec = (r<<shift)|dec;
bin /= 10;
}
printf("%d", dec);

}

[rudrachakraborty]

Thank you, sir. This really helped me with my paper 1 programming practice. From London

[Khadra]

if i want to check if the number have only 1 and 0 how can i do that?
if it has other number, send error message :(

[arnoldgatchalian]

Thank you I've learned a lot from you

[tumutarun]

Upload all videos in c language for learners

[YashDEVELOPER]

Very beautiful explanation sir.. u r amazing 🙏

[HuynhThanhThuan]

Very easy to understanding, thank you dear Sir.