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Derivative of e^cosx with Chain Rule | Calculus 1 Exercises

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We differentiate e^cosx using the chain rule. The outside function f(x) is f(x) = e^x, and the inside function g(x) is g(x)=cosx. Then, f(g(x)) = e^cosx, so we see we've identified the outside and inside functions correctly. Applying the chain rule, we have the derivative of f(g(x)) is f'(g(x))*g'(x) = e(cosx)*(-sinx). #calculus1 #apcalculus
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★DONATE★
Thanks to Loke Tan, Matt Venia, Micheline, Doug Walker, Odd Hultberg, Marc, Roslyn Goddard, Shlome Ashkenazi, Barbora Sharrock, Mohamad Nossier, Rolf Waefler, Shadow Master, and James Mead for their generous support on Patreon!
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