Solving a multi step equation with two sets of parenthesis ex 17, (c+3)–2c–(1–3c)=2

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👉 Learn how to solve multi-step equations with parenthesis. An equation is a statement stating that two values are equal. A multi-step equation is an equation which can be solved by applying multiple steps of operations to get to the solution.

To solve a multi-step equation with parenthesis, we first use distribution property to remove the parenthesis, then we combine like terms by taking the variable terms to one side of the equality sign and the constant terms to the other side of the equation and evaluate them, and then we can isolate the variable by multiplying both sides by the reciprocal of the coefficient of the variable.

Organized Videos:
✅How to Solve Multi Step Equations
✅How to Solve Multi Step Equations with Variables on Both Sides
✅How to Solve Multi Step Equations with Parenthesis on Both Sides
✅How to Solve Multi Step Equations with Parenthesis
✅How to Solve Multi Step Equations with Brackets

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Im struggling with a problem. When the a would be on the left side of the bracket for ex 14(a+2)=18 then i get it right all the time but, when its on righthand side for ex 2(23+a)=34 then i always struggle. What am I doing wrong? PLEASE HELP!

lathanreitz
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wouldnt 0c-2c=-2c + 3c = 1c How you get +2c?

reignrelic