Math Olympiad Questions by Harsh sir | Vedantu Math - 18

This video shows you how to solve this math Olympiad problem which looks easy but is tricky. Our Master Teacher Harsh Priyam sir will explain a few simple and easy steps to solve this problem. Stay tuned to @VedantuMath for more such videos.

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[KAPILGUPTAIITM]

2^300= (8)^100
3^200= (9)^100
Now you can easily see 3^200 is greater than 2^300

[gurrapusudha]

3^200 is greater than 2^300
Solution by equal the bases and seeing which power is greater

[FAUXVIKINGIITB]

3²⁰⁰ is ofc greater bcoz, it can be written as( 3²)¹⁰⁰ = 9¹⁰⁰
While 2³⁰⁰ can be written as (2³)¹⁰⁰ = 8¹⁰⁰
And, 8¹⁰⁰< 9¹⁰⁰
Hence, is the ans 🔥🔥🔥

[annanyachauhan]

This is my favorite series of all time
Thanks a lot, harsh, because of you I'm loving the numbers even harder

[aadhil__]

9^100 >8^100
Therefore 3^200 is greater

[trulysatyam]

2³⁰⁰ =(2³)¹⁰⁰ and 3²⁰⁰=(3²)¹⁰⁰
So we can find that (3²)¹⁰⁰ is bigger one.
Thankyou sir 🎉

[mokshithreddy]

Sir ji aapke liye question lekar aaya hai ji
x^x=0.25 find x ji challenge

[saurabhvedant]

Ye question toh bahot chircut sa nikla