SAT Math Section: Distance Rate Formula | SAT Practice Questions

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The answer to the train problem is C. Thats what you get if you use systems of equations. I also found a similar problem in which you would get the wrong answer by splitting the time at the end

EverythingTechTime
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Another way to do the last problem, at least if I am correct, is like this:

Stephan is driving at 40mph and Gertrude starts driving exactly an hour later. This means that Stephan is 40 miles ahead of Gertrude already. Knowing this, we can set up an equation to solve for x, where x is the total time that has passed before Gertrude caught up to Stephan:



40 (miles) + 40x (rate) = 0 (miles) + 50x (rate)

40 = 10x

x = 4

I hope this helps and please let me know if my explanation is unclear or incorrect!

j-man
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Hi Chris, SAT Expert at Magoosh. As noted in some other comments, the answer you provided for the train problem is inaccurate (the correct is choice C, not choice B). Please update or replace this video to correct this mistake. Thanks.😥

fxqjr
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Is the answer to the second question really not 1:00 PM? I thought the way to solve these problems was to have the combined speed achieve the combined distance. In this case that would be traveling 300 miles at 100 mph. This would imply 3 hours after 10, i.e. 1 PM. As you explained, at 3 hours the combined distance the trains have traveled is 300 miles (which is when they meet). Am I missing something?

alexduchnowski