Visualizing simple complex functions -- Complex Analysis 3

preview_player
Показать описание

⭐Support the channel⭐

⭐my other channels⭐

⭐My Links⭐
Рекомендации по теме
Комментарии
Автор

31:20: “the burger in the world where 5 exists” - without context, this message is delightfully absurd

synaestheziac
Автор

Thanks for every single video. I just recently found out you had this channel and can’t wait to see them all.

jorgedaniel
Автор

For somebody not familiar with complex analysis, is there any kind of companion book you'd recommend for following these? I've been using Axler alongside your series on abstract linear algebra

kaasci
Автор

Really nicely done. I also love the chalkboard work. I tell my students that nothing sound likes learning better than a piece of chalk on a chalkboard - markers DON'T do it 😊

vancenannini
Автор

At 28:27 the equation should be v = ½(u²–1) instead of v = ½u²–1

TheOldeCrowe
Автор

16:43 I hope you meant negative real axis
EDIT: You keep calling it that, and I'm not sure what you should do to fix it

romajimamulo
Автор

Finally i understand this topic thank you so much this helped a lot

aweebthatlovesmath
Автор

At 14:06, if you interpret the argument as -pi/2, the new argument is -pi/4 which is what you drew, but if you interpret it as 3pi/2, then the new argument is 3pi/4, which is what you drew for the other function. How do you know which is which?

aniruddhvasishta
Автор

14:00 If you think -i as e^i(3/4)pi instead of that negative argument you end up with a different point. What is going on?

andersok
Автор

Great video. But the font size in the mathematica is too small. I think the demostration will be much better if you enlarge the font by "magnification" in the "window" menu.

sunev
Автор

In the last expression for v there should be parenthises around u squared minus 1.

georgelaing
Автор

I'm a bit confused about the parabola at 28:42. i is a point on the line y=x+1, but i^2 = -1, and -1 is not on the parabola v = u^2-1. How could that parabola be the image in that case?

half_pixel
Автор

Isnt the reason you have to do a branch cut is if you didnt theres no way to make your squareroot functions continous? To make them singular valued really isnt a problem.

vizart
Автор

"The burger in the world where 5 exists" is what

atreidesson
Автор

is there a text book or a reference i can stufy complex analysis with this course

alfykerolous
Автор

Please somebody tell me how to solve for x^2+(y-1)^2 = 4 under w = z^2... it is not going to be a cardioid, and I am stuck.

milenamarquez
Автор

14:02 confuses me. Couldn't you say that the argument of -i is 3π/2, mapping in to the second quadrant? Equivalently, using the negative root, -i would end up in the fourth quadrant.

Toni-chzx
Автор

I'm confused by the Riemann sphere. Looks like if you match the pluses to the pluses etc then you end up gluing the 0 from the top half to the infinity from the bottom half (and vice versa). Also, I don't see how this solves the problem of it not being a function - isn't every point in the complex plane mapped to two different points on the sphere still?

Alex_Deam
Автор

Will this series cover topics like "the method of steepest descent?"

sinecurve
Автор

Can someone explain what is being said at 9.30 about everything above the x- axis getting mapped to the entire plane? I don't understand that part
thanks

mals