Angle Chasing Basic - Geometry L-7 | IOQM 2021 | IOQM Preparation | Maths Olympiad | Number Theory

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Abhay Sir is Live and in today's session, he will be teaching Angle Chasing Basic - Geometry and will be sharing tips and trick to understanding Angle Chasing - Geometry questions. Indian National Mathematical | Maths Olympiad Exam 2020 | RMO Olympiad 2020 | Olympiad 2020.

A three-hour examination known as the Indian Olympiad Qualifier in Mathematics (IOQM) conducted by the Mathematics Teachers Association (India)(MTA)(I).
The Indian National Mathematics Olympiad conducted by the Homi Bhabha Centre for Science Education- Tata Institute for Fundamental Research (HBCSE -TIFR).
The International Mathematical Olympiad Training Camp (IMOTC) conducted by the Homi Bhabha Centre for Science Education (HBCSE).

PDF Will be shared after the lecture.

Assignment Link for Today PDF Content:

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Assignment PDF -

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Let's learn All About IOQM 2020-21 ( Indian National Mathematical Olympiad /INMO 2020) by Abhay and crack Maths Olympiad 2020 at ease. Here we will cover all the information on the maths Olympiad Exam 2020 to make you understand the Maths Olympiad Preparation better.

🎯 Let's crack the Indian National Mathematical Exam 2020 with your favourite Abhay Sir, who came up with the concept that our subject will come alive in your life and your classroom.

Here’s a quick rundown of what you’re about to learn ⬇️
⚬ IOQM 2020-21
⚬ IOQM 2021
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In the end, you’ll have a handful of actionable strategies that you can use to increase your Maths Olympiad rankings.

Vedantu Olympiad School is here for you with online classes | Online Tutorial | Online Maths Olympiad ✔📚 to cover the entire syllabus of the IOQM 2020.

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Thanks for watching this session on IOQM 2020-2021 preparation by Abhay Sir. Hope you have enjoyed and learned more about IOQM 2020 and How to Prepare for IOQM Exam 2020 for Maths Olympiad 2020 (Olympiad Exams 2020).
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Kisko realise hua ki hum kuch umeed se jyadi hi geometry meh weak hai

keyurishah
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46:59 can be solved using sine rule very easily

mridultiwari
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last question can be done without any construction

ANKITGUPTA-gmmq
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Sir u teach well paar kuch kuch question pata nhi mera dimag nhi lag pata utna. So feels demotivated 😢

rashmimowale
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i think at 54:37 the answer that he has calculated as 72° is wrong because he has taken abe congruent to cde but the actual congruency is abe congruent to dce
please correct me if im wrong

kinjalraushan
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I am here for the brownie points:
Clearly AQC and PAB are congruent by the given condition and cyclicity of BFEC.
Then <AQC = <PAB implying (QFA) is tangent to PA.
Thus OA (O: circumcenter of (QFA)) is perpendicular to PA.
However QFA being a right triangle, O lies on QA.
Thus QA is perpendicular to PA. ;)

athoo
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Good morning sir, i have a doubt in finding perimeter of right angled triangle whose one leg 11cm, in that case if we check SUM OF ANY TWO SIDES MUST GREATER THAN THE THIRD SIDE, BUT we have the sides 61, 60, 11 are not sides of a tringle

swayamkrushimathtutor
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SIR WRONG PDF HAS BEEN UPLAOADED, on this lecture... Please provide the original PDF sir.. Please

harshapoojari
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90 is the correct answer to the given homework question. Please let me know if I am wrong

tusharamreliya
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Hint to H.W. question: make triangles congruent and just chase the angle

idontfeelsogood
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I have sent correct solutions to answers in physics sessions by Rohit Garg sir, so can I know wether I am enrolled free of cost in IOQJS booster batch kindly send confirmation, thanks a lot for this opportunity VOS!!!

sci-fynerd
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Sir why you are not giving a booster question now

Diya-Joshi-
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Sir your classes are really too good 👍🏼

rumadas
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Sir assignment 7 ke link open Karte to assignment 8 ke pdf open ho Raha Hai help me out sir

thanduprabhakar
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questions were really tough from the beginning, why is he saying that the questions are so easy

mohsinwara