Angle Chasing Observation | Geometry | Mathematics Olympiad IOQM 2023 | Abhay Sir | VOS

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[yuvraj]

Regarding the rmo problem, I solved it without using rotation.
Consider a point P on BC such that BP=PC. Join AP.
Construct a circle with points A, B and C. It's clear that BP, PC and AP are the radii of the circle. So PD=3x and PE=2x.
Area of triangle ADE can be written as 1/2(5x *6x). But area of a triangle can also be written as 1/2(xy sinθ), so for triangle ADE: 1/2(3√5x *2√10x sin(∠ADE)). 3√5x and 2√10x are obtained by using Pythagoras theorem in triangle ADP and APE. Since both areas are same, we can equate the relations:
1/2(5x*6x) = 1/2(3√5x *2√10x sinθ)
sinθ = 1/√2
θ = 45°

[angelinageorge]

Sir the rmo problem which you discussed can also be solved by cosine and sine rule I checked it and got 45 degrees as the answer but rotation was another level sir I don't have much knowledge own rotation so I learnt something new today

[monk_]

thankyou sir,
it was a thought provoking amazing session.
i am captivated to see such level of content free on youtube
gr8 initiative by vedantu

[nikhiljha]

HW. Q.9.
By observing isosceles triangles in the figure
180–2x+y=144—(1)
– 180–2y+x=105—(2)
3(y–x)=39
B)13

[nikhiljha]

(HW) Q.11)
By observing isosceles triangle in the figure.
2(x+y)=180–24
x+y=78°

[gamingwitharnav]

Thank you for teaching us you are the best teacher

[Allinone-qslu]

Question 5 can also be done by similarity

[Akshat-st]

Answer of Q 12- 180/7 =25.71 ~26 degrees

[ishantwankhade]

sir, From where Are you bringing this amazing Question, please tell

[sahbooom]

Sir when will the class for prime juniors in YouTube?

[SumitVerma-lgqh]

Rmo problem can be easily solved by cosine law

[vartikagoyal]

sir last question homework me question complete