Differential Equation | Variable Separable Method - Concept & Example By GP Sir

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This video lecture on Differential Equation | Variable Separable Method - Concept & Example By GP Sir With Concept & Example By GP Sir | Problems & Concepts by GP Sir will help Engineering and Basic Science students to understand the following topic of Mathematics:

1. What is Differential Equation
2. What is Variable Separable Method
3. Example Of Variable Separable Method For Differential Equation
4. Concept Of Differential Equation
5. This is helpful For CSIR NET, IIT-JAM, GATE Exams.
6. This is Part Of the Differential Equation.

#DifferentialEquation #VariableSeparableMethod #Concept #Example #ShortTrick #EngineeringMahemaics #BSCMaths #GATE #IITJAM #CSIRNET

This Concept is very important in Engineering & Basic Science Students. This video is very useful for B.Sc./B.Tech & M.Sc./M.Tech. students also preparing for NET, GATE, and IIT-JAM Aspirants.
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Time Stamp
0:00 - An introduction
0:42 - Working rule for variable separation method
2:02 - Example1. Based on variable separation method
2:56 - Example2. Based on variable separation method
4:56 - Q1. Based on variable separation method
7:35 - Q2. Based on variable separation method
9:11 - Q1. answer asked in Comment box based on variable separation method
9:30 - Detailed about old videos

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Dr.Gajendra Purohit

[IswalkarOm]

option D is correct. The final answer is (-1/b)e^-by= (1/a)e^ax+c

[HarshilAndhariya]

Option D is correct
1/a(e^(ax)) + 1/b(e^(-by))+c =0

[imranomar]

Dear Sir kindly some more questions about formation of differential equations I am very thankful to you .

[Hasinavalli]

Hello Sir
I am a teacher
Just suggest me with interactive teaching pad will more effective for teaching high school maths

[legendsaurabhmeena]

10min video covered quality content ... ..! And your one hour thanks 🙂🙏

[journeyofstudents]

Answer is Optind D
And solution of given differential equation is -(1/b)e^-by =(1/a)e^ax+c.

[ahmedsohail]

Sir, you're teaching very fast. It will be hard for some students to get what you are trying to teach.

[shakeelurrahman]

highly professional, accept my gratitude from across the border...

[AjayAjay-byiv]

Sir your teaching method is Very effective

[ejajahmed]

option D is the answer. The actual answer is (-1/b)e^(-by)= (1/a)e^(ax)+c .

[bibhurawat]

Sir home work question ke answer main thoda mistake ha 3 option main +ki jagah =hoga

[themechanic]

Today I just learnt this in class sir, now I understood better thanks a lot for your efforts sir.

[mohammaduzair]

Sir I love Your Videos Cause U only do "padhai and no bakwas" like other teachers.

[IndreshPrajapati-bw]

(-1/b)e^-by = (1/a)e^ax option b is correct. I m very thankful to you sir ❤

[आपकीआवाज-षड]

जब भी में पढ़ाई के कारण डिप्रेशन में चला जाता हुं तो आपके विडियोज मेरे लिए बहुत ही हेल्पफुल होती है
And in lastly u r not gajendra purohit sir
" You are unique Gajendra Purohit sir
Thank you sir 🥰

[masterprashant]

sir aaj meri coaching m pehli class thi toh yhi hua tha aapki video dekhkar achha laga ❤️❤️❤️❤️❤️

[praptisinghal]

Option D is the correct answer.

log(dx/dy)= ax+by

dx/dy= e^(ax+by)

dx/dy= e^(ax) . e^(by)

Rearranging:

e^(-by) . dy = e^(ax) . dx

Integrating both side we get,

(-1/b)e^(-by) - (1/a)e^(ax) = C

[acemaster]

sir ans is d :- -1/b e^-by=1/a e^ax+c
in 4 mins

[vishal]

C option and = in between equation -1/be^-by=1/ae^ax+c

[shivamupadhyay]

log(dy/dx)=ax+by

dy/dx=e^(ax+by)

dy/dx=e^(ax).e^(by)

e^-(by)dy=e^(ax)dx

-1/b e^-by= 1/a e^(ax) + c

hence option C is correct.