Energy of CT Signals (Solved Problems) | Part 1

Показать описание

Signal and System: Energy of Continuous-Time Signals (Solved Problems) | Part 1
Topics Discussed:
1. Examples of energy calculation in case of continuous-time signals.
2. The energy of exponential signals.
3. The energy of infinitely converging signals.
4. Effect of time-reversal on the energy signals.
5. Effect on the signal's energy when two signals are added.

Music:
Axol x Alex Skrindo - You [NCS Release]

#SignalAndSystemByNeso #Signal&System #EnergySignals

Рекомендации по теме

Комментарии

if my graduation got completed in EEE only becz of neso academy 🖤 ....not even my college after paying lot of fees 😬

sushmasush

Sir in second problem
We can use time reversal property
The graph will be opposite to the first one
But in that graph u(t) - infin to 0 is 0
But u are don't consider that one
So I confiuse
Pls reply my question sir

unknownm

Sir, in second problem because of t<0 u(t) is 0 then whole function will become 0. Can u explain how we have to consider that sir?

pawankumarreddy

Bro your hand writing is awesome! Keep it up!

AJK-ajk

I am pretty sure the third case is wrong: There are again 3 cases, a< 0, a>0 and a=0. When a=0 we just have the equation of x(t) = 1, a horizontal line that stretches in both directions infinitely so obviously E-total is infinity. When a > 0, we have X3(t) = e^(-at)*u(t) + e^(-at)*u(-t). When a > 0, we have an exponential decreasing function such that when t < 0 it diverges and when t > 0 it converges. So the e^(-at) portion, starting at (0, 1) it decreases and converges for t > 0 and for t < 0 it diverges, but when you multiply by u(t), the diverging part ( t < 0) disappears, it is equal to 0 because u(t) is 0 for t <0. That's the first part of X3(t), now looking at the second part where we have e^(-at)*u(-t), we still have the same decreasing function such that when t < 0, it diverges and when t > 0 it converges. However when we multiply by u(-t), the converging part of e^(-at), when t > 0, it disappears, it is equal to 0 because u(-t) = 0 for t > 0. Adding both of those portions together just produces a normal decreasing exponential function where it diverges for t < 0 and converges for t > 0. Case 3 produces the opposite except now we have in the end a exponential increasing function. All 3 cases produce functions in which total energy is infinite.

rationalthinker

sir, am not sure but the value of energy in 2nd qustn should be -1/2a

joeljohnson

All the things going gud, but conduct one lecture for Questioning in comment box

WaleedAbdullahkEE

Sir, you haven't taken the case, when t<0 in question 1...

pandeyautkarsh

can anyone please explain the case for a<0, in problem 1
and also please explain the answer of second problem.

meghana

sir i dont konow whiy after time reversal my energy is coming negative

princekonwar

Sir you 3rd on question graph plotted is wrong because the value of x(3) will always be equal to 2 at time t=0. So please correct it

rangbahadursingh

Sir in second and third case ... Why we are considering from -infinty to 0?.... Didn't We have unit step function there which is 0 from minus infinity to
Plz respond sir

sultanshaik

in the third example i think you did make a mistake when you did (x1 + x2 )^2 you will find a different value wich is infinity and i don't know why

marouanebicher

for the second case, we are taking the integral this time from 0 to negative infinity and my final result is infinity, so how come the second one has an answer same to the first?

rashedalmulla

Sir a small mistake is there in second condition when energy becomes infinite the exponial must be increasing but u take negitive exponitial signal in second case aslo

AvinyaSolutions