If x=(3+root 8), find the value of x²+1/x²

[pricelessheritagewithanupama_t]

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[gnanambigaimaheshbabu]

Sir sum is wrong
The answer is :
x = 3 + root 8
x² = (3 + root 8)²
by(a + b)²
= 3² + (root 8)² + 2×3×root 8
=17 + 6×root 8

1/x² = 1/(17 + 6×root 8)
=17 - 6×root 8
by rationalizing the denominator

x² + 1/x² =17 + 6×root 8 + 17 - 6×root 8

=17+17
=34

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