Calculating the Gravitational Force

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Answer = 126 N

045 - Calculating the Gravitational Force

In this video Paul Andersen explains why astronauts are weightless. He also explains how Newton's Universal Law of Gravitation can be used to calculate the gravitational force between objects.

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Music Attribution
Title: String Theory
Artist: Herman Jolly

All of the images are licensed under creative commons and public domain licensing:
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You explained in a few minutes what my professor took an entire lecture to explain and I had to come to you to understand it. You have valuable skills in communicating these concepts, thanks so much!

dtagg
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Best teacher I've ever had <3 thank you for what you do.

Sincerely,
Every Lost Person in Physics

nikhiMD
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You are literally awesome! I'm supposed to go to the best school in the Netherlands and my teachers don't even touch this..

ikleinveld
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Very well explained. It shows that you really know what you're talking about. Thumbs up for you teacher.

rider
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Your videos are really really good, that I even recommended my teacher to watch your videos because she was having a hard time understanding a few concepts. Really appreciate your videos... they are really helpful...

iamthestrongest
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How did you get the 1.5 x 10 -10? What operation happens between G constant and 2.25?

totilujan
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Thank you so much. People like you are true heroes. I'm certain that your videos are going to help me achieve my goals in my first university physics classes!

esquiro_cody
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Thanks! Needed this for my astronomy class.. It's fun to do.

LoboOutdoor
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but had a hard time understanding the last step o0f the first problem

danthurineeraja
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4.45 Where did the 2.25 go? and Why does the -11th power turn into -10

codingwithbobby
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Awesome. All doubts cleared!!!
We dont have such brilliant teachers in India and that's why Indian educational system is nothing when compared to America's and other countries.

mr.unknown
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Actually in the perfect round revolution gravity is taken out, the newton intuition and explanation is half right half wrong.
The force of gravity cancels out in the formula. In an elliptical revolution the condition of falling and missing fits better,
but again just in the falling pathway. Isn't it?

GoodTime-znbg
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2:34 did you mean Time or Distance. I think you mean Distance because in relation to earth a human simply doesn't have the mass to stay in orbit unless moving at a unfathomable speed.. at least in my opinion of course

Ifinger
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Always messed with my head that the more massive the object, the more gravitational force applied, but the acceleration remains the same no matter the mass of the object. I still can't really articulate why that is.

originalSPECTER
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It would be awesome if that last problem can be worked out with out a calculator! Studying for the MCAT and didnt get 126N lol

stephaniecantu
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g is the average density of mass. it's actually a wave of probability dependant on the frequency of quantum interactions required to contain energy as mass. the time required for each interaction. relative to the time of its souroundings.
movement of mass over the same distance at less speed. requires less force. so mass with excess energy moves faster time. mass that looses energy. moves towards slower time. a unified theory of gravity.

atticuswalker
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Makes so much sense! But then what happens when a rocket is traveling perpendicularly away from the earth toward the moon, not accelerating but moving at a constant speed? Is there a small gravity toward the bottom or engines of the rocket since this is in the direction of the earth? At some distance weightlessness should balance between the pull of the moon and earth. I imagine there’s a name for this equilibrium point in space

michaellaforte
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I don't understand why the force of attraction is equal, then if the earth and the moon were stationary the gravity should move the two objects at the same speed right? That's strange

alessandromariani
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isn't newtons a measurement of weight, not gravitational pull? did you mean that the objects that were 3 Kg would weigh
1.5*10^-10 newtons under each others gravitational force? other than that small miscommunication this is a good explanation on the math.

TriviaQuizocity
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Thank you so much, I really appreciate

abugreayingangbagerald