4 Methods to Find Minimum Value From Quadratic Equation

[nabihah]

I love it when he says, "Do you understand?" LMFAOO

[shuidongliu]

You could also use differentiation to do this as well, no? There's a 5th method.
if f(x) = x^2 - 8x + 12
then f'(x) = 2x-8
turning points are when rate of change is 0 so set f'(x) to 0:
2x-8 = 0
2x = 8
x = 4
plug back into original equation
f(4) = 4^2 - 8(4) +12
= 16 - 32 + 12
= -16 + 12
= -4
Thus, minimum value is -4.

[strnoob]

2 steps for vertex of a quadratic equation ax²+bx+c
1. Use -b/2a you will get the x of the vertex.
2. Then plug that x into the original equation to get y. Easy.

[Pastozafaire]

At 6:48, the graph intercepts the X axis at (2, 0) and (6, 0) and the axis of symmetry is the line x=4.

[HiHowAreYa]

Thank you sir, please help me find the minimum value of y=2x^2-8x+10

[ndianzon]

Sir Anil Kumar, sorry to correct you but the partial factor is wrong because x=0 & x=8 are not the x-intercepts of the parabola function f(x) = x^2 - 8x + 12, the correct x-intercepts are x=2 & x=6 from intercept form of parabola function f(x) = (x - 2)(x - 6).
x = (2+6)/2 = 4, x=4 is the axis of symmetry. Evaluate f(x): f(4) = (4)^2 - 8(4) + 12 = -4 or f(4) = (4 - 2)(4 - 6) = -4. So the minimum value of the parabola is -4. It just coincidentally happened that when you solved axis of symmetry x = (0+8)/2 = 4 for partial factor and therefore conclude minimum value is -4 which you based on your first solved vertex (4, -4). :)

[rajasamo]

We can find with method
Let f(x)=x^2-8x+12
By using formula for x

x=-b/2a
Here a=1 b=-8 and c = 12
So, x = -(-8)/2(1)
x=4
Now finding y
Put x=4 in equation above
Y=(4)^2-8(4)+12
Y=16-32+12
Y=28-32
Y=-4
Therefore (x, y)=(4, -4)

[FluidLikesMath]

I have a question is: If y=∣x−3∣+(3−x)^2 − 5, what is the value of x - y when y is the minimum?

[sleepingpills]

Sir i want to know how the coordinates of vertex came (4, -4)

[dr.rahulgupta]

Sir There is 5'th method also .Put y = ax^2+bx +c then find dy/dx = 2ax +b and equate it to zero. This gives x =--b/2a .Then substitute this value of x in y . DrRahul Rohtak Haryana India

[bennyuchiha]

This awesome others have been confusing me all over youtube but Here you gave me what I'm looking for straight to the point, thanks

[sadeedwaseem]

2nd method is not used correctly. this method could only be used when the graph passes through the origin. in this equations case it doesnot.

[sachinlohani]

Thanks A lot Sir I've exams after 1 months this help me a lot. Love you sir.

[thejamminguitarist]

How do you solve the same question with the Eqn X2 + 4x + coming -2+√2

[anaizecardinal]

It helped me, but this is not the same method we learned.

[arskitchen]

What is the maximum and minimum value of x square - x + 7

[beinghuman]

Sir maximum and minimum value of a polynomial Kahi value nikal neka formula hai na ye Max n min value of a quadratic polynomial ka nikal neke formula hai n min value of a cubic Polynomial n higher order Polynomial ka value kese nikalte plzz batana😧😭

[jpprakash]

i had no lit bit of knowledge about maxima and minima....so please video to learn maxima and minima

[crazypvpHow]

SOmething else useful: the y-coordinate of the vertex will be c-(b^2/4a)

[lubnakhanum]

F(x)=(X+2)^2 how can i solve this problem