JEE Advanced 2020 Solutions | 🤔 FAIR or UNFAIR ? | Thermodynamics #BonusQuestion #IIT

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A question yet again given BONUS in JEE Advanced 2020. This question is from Thermodynamics and came in paper 2.

JEE Advanced 2020 | Paper 2 | Thermodynamics Question
A thermally isolated cylindrical closed vessel of height 8 m is kept vertically. It is divided into two equal parts by a diathermic (perfect thermal conductor) frictionless partition of mass 8.3 kg. Thus the partition is held initially at a distance of 4 m from the top, as shown in the schematic figure below. Each of the two parts of the vessel contains 0.1 mole of an ideal gas at temperature 300 K. The partition is now released and moves without any gas leaking from one part of the vessel to the other. When equilibrium is reached, the distance of the partition from the top (in m) will be _______ (take the acceleration due to gravity =10 ms−2 and the universal gas constant = 8.3 J mol−1K −1 )

Timestamp :
00:00 Introduction
00:32 Question Statement
02:18 Correct Solution
09:14 Incorrect Solution but Same Result
10:54 Why Bonus ? Unfair to many ?

JEE Advanced 2020 Solution | JEE Advanced Bonus Question | JEE Advanced 2020 Thermodynamics Question | How to Solve JEE Advanced 2020 bonus question ?

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About Faculty-
Completed Bachelors and Masters from IIT Kharagpur. Having an experience of +4 Years in teaching I reckoned the urge within me to help students appreciate the subject by delivering the toughest concept in simplest manner through practical demonstrations and visual aids.

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MUST WATCH for all true JEE Advanced Aspirants.
Please 👍 Like and Comment !
A lot of effort goes into creating such content and your support will only encourage to make more.
00:00 Introduction
00:32 Question Statement
02:18 Correct Solution
09:14 Incorrect Solution but Same Result
10:54 Why Bonus ? Unfair to many ?

mohitgoenka
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KEY ERROR - Lack of understanding of the word 'system'. Here the system is the gas + piston system, NOT just the gas, which is why although total internal energy of the SYSTEM is constant, the internal energy of the gas is NOT constant.

cyphexal
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You and Ashish Arora sir only pointed it out sir even in reputed coachings solutions they have solved by wrong method

prathamdani
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this kind of content only makes this channel, one the best channel on whole yt!!...thank you sir, ur exaplation is really very powerful and highly specific!!

anuragkumar
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Actually I did the solution without watching the solution, by ignoring gravity ka work by incomplete concept. Now, understood 🙌👍🏻

joshhr
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you teach advance questions like butter i feel everything getting into my mind smoothly....

sara-bzis
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Sir i also did by incorrect method while solving on my own. Now total concept clarity!!🤎🤎

sanchitmukherjee
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Sir i also didn't consider Work done by gravity when i was solving on my own 😀
Thanks for concept clearance 🙏🏻

shreyanshtiwari
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*I am dropper and now i am able to recognise which YT channel are good for competition. According to me EDUNITI BY MOHIT SIR, P.GALAXY ASHISH SIR, PHSICS siddhant SIR, RAJWANT SIR PW are one of the best teachers in YOUTUBE to sharpen the concept.*

nehasupakar
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Bhaiya please discuss such tough and good questions daily so that our physics can get stronger

sarojsaroj
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Actually, the main point is that internal energy of the system is constant as no energy exchange is possible
but a lot of people mistook internal of system as internal energy of gas
since internal energy of the system is = internal energy of gas ( of both partitions ) + potential energy of the disc
take bottom of container as reference to write potential energy
and just apply energy conservation and force balancing u get the same result..

atulsm
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A channel only dedicated for our study !! Hats off sir !! 👍👍👌

neetclimax
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Sir you really do very good work because every student needs this type of content this time thank you sir

luckyshorts
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Sir please bring advanced problem series of fluid properties. I have completed the other parts and it was very beneficial.

AnuragGupta-zjwm
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Completed : ✅
My approach was right, but got stuck since they didn't give monoatomic/diatomic. For Ideal gases, we can assume them to be ideal gases if nothing else is specified. 5:10
Not Meant for Revision ❌
Day : 10

BitGamerYT
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Happy teacher s day sir u r awesome and explanation is very beautiful, even my young brotherin class 11 understand the tough advanced level problems from ur video

amitabhkumar
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Just wow !!
Def unfair, papers like these make it tough for the worthy ones

akshatjain
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Thank you sir🙏
please make a video on air bubble inside water question of jee adv 2020

AnkitPandey-eswk
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Moral of the story for IIT KGP this Hawa mein udne wale questions Dene ki koi jarurat na level question do....reaserch level nahi...

yashkant
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happy teachers day sir
you are the only one who made physics easier for me in mains and also hoping the same for advanced
I wish next year u will cross 100k subs

Bunnycroons