SOP and POS Form : Non Canonical to Canonical Form Conversion of Boolean Expression

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In this video, the Conversion of Boolean Expression from Non-Canonical to Canonical form is explained with solved examples.

Timestamps:
0:00 Introduction
0:37 Sum of Product Form: Non-Canonical to Canonical Form Conversion
3:00 Example 1
5:45 Example 2
7:43 Shortcut method for Non-Canonical SOP to Canonical form Conversion
9:52 Product of Sum Form: Non-Canonical to Canonical Form Conversion
12:35 Shortcut method for Non-Canonical POS to Canonical form Conversion
14:17 Example 3

Digital Electronics (Playlist):

SOP and POS Form: Minterms and Maxterms

This video will be helpful to all the students of science and engineering in understanding the conversion of Boolean expression from Non-Canonical to Canonical form.

#ALLABOUTELECTRONICS
#SOPandPOSForm
#SOPandPOSform

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Timestamps:
0:00 Introduction
0:37 Sum of Product Form: Non-Canonical to Canonical Form Conversion
3:00 Example 1
5:45 Example 2
7:43 Shortcut method for Non-Canonical SOP to Canonical form Conversion
9:52 Product of Sum Form: Non-Canonical to Canonical Form Conversion
12:35 Shortcut method for Non-Canonical POS to Canonical form Conversion
14:17 Example 3

ALLABOUTELECTRONICS
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You discuss all the topics in detail, please upload remaining videos on digital electronics . I think the channel " All about electronics " and " neso academy " are the best channel in youtube for digital electronics. THANKS 👍👍👍

ajiteshkumar
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One should always be proud of their work. I bow to you with great reverence

girikeshav
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Thanks alot sir, you have really saved me, to be honest you are better than our professor. you deserve a big thumb

abubakarusman
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Thanks so much! I really appreciate the excellent work and effort you put in. I was struggling with these concepts but all your videos are saving me. Many blessings your way❤🙏

OKPB
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Here from IITG, this channel is literally a gem❤

zarapkarajinkya
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9:51, Answer is
Canonical SOP form = Sigma ( 1, 5, 8, 9, 10, 11, 13 )
Canonical POS form = pi ( 0, 2, 3, 4, 6, 7, 12 ).

ajiteshkumar
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I am getting answer for last question as:-
pie 2, 5, 6, 10, 12, 13, 14, 15
sigma 0, 1, 3, 4, 7, 8, 9, 11

All are getting different @ABOUT ELECTRONICS please provide correct answer

creativeprojectsmaker
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Thank you so much sir!!!❤️
It' become so easy to solve now and it's only because of you✨..

shubhisingh
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Thankyou, sir 😊😊 it is really helpful video aase he video banete raheye.

Imkids
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hi can you please show how to convert non canonical sop to minimum sop form?

rezwanaroza
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Your understanding and explanation is to good sir 🫡

UE_devlover
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at last pi (2, 5, 6, 10, 12 , 13, 14, 15)

chiranjeevipathipati
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At 11:52. the expression should be:
which surely gives 0, 1, 4, 6

usmanatharkhan
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Is there a mistake at 11:48? Isn't it A'CB' = m5, not m6?

tcv_sacred
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at around 5:20, how does he get the minterm numbers of m7, m5, m4, m6, m3?

malik
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how can we just remove terms like that

siddhantsingh
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9:51 --- The answer is F = SIGMA(3, 7, 11, 12, 13, 14, 15) and F = Pi(0, 1, 2, 4, 5, 6, 8, 9, 10)???

debmalyamukherjee
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Are non-canonical form and standard form same thing?

shaylasamara
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12:00 the pos form answer is 0, 1, 4, 5 but u have written 0, 1, 4, 6

s.jayanthKumar-wq