Converting SOP to POS Expression using Boolean Laws and DeMorgan's Theorem

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This video explains converting SOP expression into POS expression straight from the given canonical/non-canonical expression by applying DeMorgan's Theorem and other Boolean Laws.

*This video is made for assignment purpose*
  1. Aliff Haziq
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Комментарии
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You saved my life before this final thank you so much

trishasriram
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The best explanations made, I clearly understand. Thank you so much. Keep up the good work.

shaikdawoodansarijainulabi
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Thank you very much for this detailed explanation, now I really understand every detail of the conversion !!

tabithatheissen
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Thanks very much for your Splendid explanation.

promotepngculturestyles
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very very good expalanation ...easy too

pratyushraj
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why are we using 7 in the second question why not end on 6

Tenz
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can somebody simplify this boolean expression?? using long method

XXY + XXZ + XY'Z + XYZ' + XYY + XYZ × X'YZ' + YY'Z + XYZ' + X'Y'Z' + XZ'Z' + YZ'Z'

isaiahdurantelor