Complex Analysis: The Integral Inequality

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Today, I present a proof for the "integral inequality" which states that the absolute value of an integral is bounded above by the integral of the absolute value.
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this is sometimes referred to as the triangle inequality for integrals

cletushumphrey
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Wow, thank you so much. I was looking for a proof of this and your way of explaining things is so clear.

xulq
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Dear QN³ ...
Please make some videos about Mapping (conformal mapping and ... ).
Thank you so much

wuyqrbt
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i need solve the upper bound of absolute value of integral(x^2+y^2)where c is line from _i to i

beroali