Polynomials | Concepts and Important Questions | Chapter 2 | Class 9 | Maths | BYJU'S Exam Edge

"In this Exam Edge session, we discuss all the concepts and important questions from the chapter ""Polynomials"".

In this class, we look at
a) Introduction to Polynomials
b) Polynomials in One Variable
c) Zeroes of a Polynomial
d) Remainder Theorem
e) Factorisation of Polynomials

Grade: 9
Subject: Maths
Chapter: 2"

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[BYJUSClass]

➡Download Classnotes for the session:

[pratibhatiwari]

A polynomial having its highest degree zero is called a constant polynomial. It has no variables, only constants. For example: f(x) = 6, g(x) = -22, h(y) = 5/2 etc are constant polynomials. In general f(x) = c is a constant polynomial.

[drawwithkrushnali]

Wonderful session mam very important session for us😊❤ score 38+5 hw answer a) 0 b)-136/27

[Amrita_Verma]

Thankyou you for this session mam this session is very help ful for me 😃😀😄😄❤️❤️❤️❤️
Homework Answer
Question 1: 4
Question 2: –32/27 =

[DileepKumar-pzfu]

Thank you for the session mam😊😊😊
Hw ans:a)0 b)-136/27

[kiran-]

You explain very nice really it's an unforgettable explanation

[Prabhu-ks]

Mam u ar session is very good mam please make a session on, mid term exam imp questions

[deepakini]

I got 39/40 + bonus question and hw ans : 1) 0 2) -136/27

[AditiSingh-zo]

Thank you ma'am you're the best

I like this session
I find this session useful because in session we revise the chapter for half yearly exam and I am sure who is watching this lecture daily he/she doing fantastic in their exams.

Score = 35/ 40
Homework answer is =
i) x^3 - 2x^2 - 4x - 1
(-1)^3 - 2 (-1)^2 - 4(-1) -1
-1-2+4-1
-3+3 = 0
So reminder is 0

ii) x^3 - 6x^2 +2x - 4
Value of g (x) = 2/3
(2/3)^3 - 6 (2/3)^2 + 2(2/3) -4
8/27 - 8/3 + 4/3 -4
(8 - 72 + 36 -108) / 27
-136/ 27
So reminder is = -136/27

[pattnaikishita]

Thank you very much for the Session ma'am!!It was a fruitful one :)
H.W question (answers)
(i) remainder=0
By putting the value as (-1) we get the remainder 0
(ii) remainder -136/27
By putting the value as 2/3 we get the remainder -136/27

[pratibhatiwari]

Zeros of a polynomial can be defined as the points where the polynomial becomes zero as a whole

[kairavi]

How is the degree not defined ? It can be anything but the ans will remain 0

[arpitasingh]

Maths is my favourite subject I got 40/40

[MadanMaiti-ze]

Can you find the zero polynomial of p(x) = x² + 1

[Knowledgeablebees]

Thank you mam your explation is super I like your voice ❤❤

[alpha_ace]

Whenever Arsh ma'am said 'hain na bachcha' I feel blessed.😇🥳 we love Arsh ma'am♥️✨

[astha--]

Thanks for the session mam! Although I missed it but I will surely re-watch the session 😄
1) QUESTION -1:40:23
i)Answer-
P(x)= x³-2x²-4x-1
Since, x+1=0.... X=(-1)
P(-1)=(-1)³-2*(-1)²-4(-1)-1
Or, (-1)-2(1)+4-1
Or, -4+4=0
Thus, reminder is 0
ii) answer-
P(x)=x³-6x²+2x-4
1-3x/2=0.... -3x/2=-1.... x=2/3

Or, 8/27-6(2*2/3*3)+4/3-4
Or, 8/27-8/3+4/3-4
Or, -4/3-4+8/27
By taking LCM,
-16/3+8/27.... -144+8/27.... -136/27
Thus reminder=(-136/27)
I will watch the session again and will tell my marks 😄