Sides AB and AC and median AD of a triangle ABC | Exercise 6.3 Q14 (Important)

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Exercise 6.3 Question 14 Class 10
An important question of Triangles Exercise 6.3 📝

Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that Δ ABC ~ Δ PQR.

HINT of Exercise 6.3 Question number 14 class 10 Maths 💡
1. Do the construction
2. Use SAS congruency, then CPCT i.e Corresponding Parts of Congruent Triangles.
3. Afterwards, use SAS similarity to show that Δ ABC ~ Δ PQR.

Read it 📖 :
INTRODUCTION
Two figures are said to be congruent, if they have the same shape and the same size.
Two figures having the same shape (and not necessarily the same size) are called similar figures.
All congruent figures are similar but the similar figures need not be congruent.
Two polygons of the same number of sides are similar, if (i) their corresponding angles are equal and (ii) their corresponding sides are in the same ratio (or proportion)

Note📝
The above question is taken from NCERT class 10 chapter Triangles Question 14 of Exercise 6.3.

Practice :
D is a point on the side BC of a triangle ABC such that ∠ ADC = ∠ BAC. Show that CA^2 = CB.CD.

Revise✍🏻:
Circles:

Real Numbers:

Polynomials

Quadratic Equation

Trigonometry

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Note 📋
It's an interesting and important problem. Do practice it 😌

If you have any doubt, feel free to ask ☺️

RHAcademy_
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What an explanation....great mam ..
Thank you so much😊

sasmitamuduli
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I am district topper in rewari cbse with 99.8℅

prince_gaming
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Thank you ma'am
You made it very simple

Dakshjangi-
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You can simply make x=y since you proved them similar

Espionage
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Thank you Mam for you Best Explaination 🙏🙏
Mam In step 4 you wrote
angle BAS = Angle QPR (from eq 7), But it should be from (eq 8)
*** Step 2
CE/RS = AC/PR = AD/PM (from eq 3 & 4 (you wrote)) won't it be from eq & 4 ???

hetulpatel
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This is my 5th time watching this video 😂

malathijithin
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Loved your way of explanation, thank you 😊☺

vaibhavpandey
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Ma'am by cost se have AEC=PSR(ANGLES) that is x=y and BAD=QPM (ANGLES) because those are also x and y then why prove the whole thing again

BeastGamer-
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Exam ke 1 din pehle padhne wale like karo 😂

nigga_chan_
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I just don't like her, I don't know why but I really hate her attitude

aryasharma
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if Angle 1 is equal to angle DEC by cpct in the starting and similarly angle 3 is equal to rnm by cpct as well, then why can't we just prove Dec is equal to rsm when making the triangles similar, so that with that, angle 1 is equal to angle 3 as well and angle cad is equal to rpm to tha hi by similarity, dono ka add karke ho to jaana, baar baar kyu Kar rahe hai, anybody please tell that why no one on yt is doing it this way??

RajniKalra-oote
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What a explanation mam!😊
Thanks a lot ..

KuldeepKumar-ylzc