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Example8 -Ncert-the sides AB and AC of ∆ABC are produced to points E and D respectively.-Class9

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Example8 -Ncert-Lines and Angles- Class9
In Fig. , the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O, then prove that
∠ BOC = 90° –1/2 ∠BAC.
In Fig. , the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O, then prove that
∠ BOC = 90° –1/2 ∠BAC.
Example8 -Ncert-the sides AB and AC of ∆ABC are produced to points E and D respectively.-Class9
In fig 6.38 the sides AB and AC of ∆ABC, Prove ∠BOC = 90°–1/2 ∠BAC | Example 8
In Fig. the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO
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