Evaluate the following limit: `lim_(x-mtpi/2)(e^(cos x)-1)/(cos x)`

preview_player
Показать описание
Evaluate the following limit: `lim_(x-mtpi/2)(e^(cos x)-1)/(cos x)`
  1. Doubtnut
Рекомендации по теме
Evaluate the following 0:01:28

Evaluate the following limit: `lim_(x-mtpi/2)(e^(cos x)-1)/(cos x)`

Evaluate the following 0:02:11

Evaluate the following limit: `(lim)_(x-mtpi/4)(2-cos e c^2x)/(1-cot x)`

Evaluate the following 0:03:11

Evaluate the following limit: `(lim)_(x-mtpi)(1+cos x)/(tan^2x)`

Evaluate the following 0:01:33

Evaluate the following limit: `(lim)_(x-mtpi/6)(cot^2x-3)/(cos e c x-2)`

Evaluate the following 0:01:28

Evaluate the following limit: `(lim)_(x-mt0)(sin2x)/(e^x-1)`

Evaluate the following 0:01:40

Evaluate the following limit: `(lim)_(x-mtpi/4)(1-t a n x)/(1-sqrt(2)s in x)`

Evaluate the following 0:02:03

Evaluate the following limits: `lim_(xto0)((e^(2+x)-e^(2))/(x))`

Evaluate the following 0:01:16

Evaluate the following limit: `(lim)_(x-mtpi/4)(1-t a n x)/(x-pi/4)`

'Evaluate the following 0:01:38

'Evaluate the following limit: `(lim)_((1-cos m x)/(1-cos n x)`'

if `lim_(x- gt0) 0:02:09

if `lim_(x- gt0) (ae^x-b)/x=2` then `a&b`

Evaluate the following 0:01:40

Evaluate the following limit: (lim)_(xrarrpi/4)(1-t a n x)/(1-sqrt(2)s in x) | 11 | LIMITS | MAT...

Evaluate : lim 0:04:10

Evaluate : lim x → π/6 (cot²x - 3)/(cosecx - 2)

Find the value 0:03:47

Find the value of `lim_(x- gt 0) (sqrt2 - sqrt(1+cos x))/sin^2 x`

Evaluate the following 0:03:18

Evaluate the following limits: `lim_(xto(pi)/(4))((cosec^(2)x-2))/((cotx-1))`

Evaluate `lim_(x to 0:02:08

Evaluate `lim_(x to pi)((1+cosx)/(tan^(2)x)).`

Evaluate the following 0:04:10

Evaluate the following limits : lim _x →∞sin(a/2^x)/sin(b/2^x)

Limit of (2x 0:02:53

Limit of (2x - pi)/ (cos x) as x approaches pi/2

Evaluate lim (x 0:07:25

Evaluate lim (x → π) (√(2 + cosx) -1)/(π - x)²

`lim_(x- gt(pi/2))(cosecx-1)/cot^2x` equals 0:02:37

`lim_(x- gt(pi/2))(cosecx-1)/cot^2x` equals

JEE MAINS 2018 0:04:01

JEE MAINS 2018 Evaluate `lim_(x to pi/4) (1-2sin2x)/(1+cos4x)`

lim x→π/2 (π² 0:00:50

lim x→π/2 (π² - 4x²)/sin(4x) = ? Solve WITHOUT using L’ Hopital’s Rule. Given lim x→0 sin(x)/x = 1....

(i) `lim_(xto(pi)/(2))(1+cos2x)/((pi-2x)^2)` (ii) 0:16:39

(i) `lim_(xto(pi)/(2))(1+cos2x)/((pi-2x)^2)` (ii) `lim_(xto0)(1-cosxsqrt

Lim x tend 0:00:11

Lim x tend to pi/2 secx-tanx #viral #mathmetics #maths

`lim_(x- gtpi/4)(cotx-1)/(c o 0:01:46

`lim_(x- gtpi/4)(cotx-1)/(c o s e c^2x-2)`