filmov
tv
Evaluate the following limit: `(lim)_(x-mtpi/4)(2-cos e c^2x)/(1-cot x)`
Показать описание
Evaluate the following limit: `(lim)_(x-mtpi/4)(2-cos e c^2x)/(1-cot x)`
Doubtnut
Рекомендации по теме
0:02:11
Evaluate the following limit: `(lim)_(x-mtpi/4)(2-cos e c^2x)/(1-cot x)`
0:02:30
Evaluate the following limit: `(lim)_(x-mtpi/4)(sqrt(2)-cos x-sin x)/((4x-pi)^2)`
0:02:58
Evaluate the following limit: `(lim)_(x-mtpi/4)(cos x-s in x)/((pi/4-x)(cos x+s in x))`
0:01:40
Evaluate the following limit: `(lim)_(x-mtpi/4)(1-t a n x)/(1-sqrt(2)s in x)`
0:01:16
Evaluate the following limit: `(lim)_(x-mtpi/4)(1-t a n x)/(x-pi/4)`
0:03:18
Evaluate the following limits: `lim_(xto(pi)/(4))((cosec^(2)x-2))/((cotx-1))`
0:03:11
Evaluate the following limit: `(lim)_(x-mtpi)(1+cos x)/(tan^2x)`
0:02:45
Evaluate the following limit: `(lim)_(x-mtpi/8)(cot4x-cos4x)/((pi-8x)^3)`
0:03:07
Evaluate : lim x → π/4 (cosec²x - 2)/(cotx - 1)
0:01:33
Evaluate the following limit: `(lim)_(x-mtpi/6)(cot^2x-3)/(cos e c x-2)`
0:01:28
Evaluate the following limit: `(lim)_(x-mtpi/3)(sqrt(3)-t a n x)/(pi-3x)`
0:07:24
lim x tends to pi/4 (4√2 - (cos x + sin x)^5)/1- sin 2x
0:04:15
IIT JEE LIMITS AND DERIVATIVES Evaluate: `('lim')_(xvecpi/4)(sqrt(2)cosx-1)/(cotx-1)`
0:07:25
Evaluate lim (x → π) (√(2 + cosx) -1)/(π - x)²
0:01:40
Evaluate the following limit: (lim)_(xrarrpi/4)(1-t a n x)/(1-sqrt(2)s in x) | 11 | LIMITS | MAT...
0:00:11
Lim x tend to pi/2 secx-tanx #viral #mathmetics #maths
0:01:10
Write the value of `(lim)_(x-mtpi//2)(2x-pi)/(cos x)`
0:02:24
Evaluate the following limit: (lim)_(xrarr(3pi)/2)(1+cos e c^3x)/(cot^2x) | 11 | LIMITS | MATHS ...
0:03:06
Evaluate the following limit: `(lim)_(x-mta)(cos x-cos a)/(sqrt(x)-sqrt(a))`
0:01:56
`lim_(x- gt(pi/4)) (sqrt(2) cosx-1)/(cot x-1)`
0:01:46
`lim_(x- gtpi/4)(cotx-1)/(c o s e c^2x-2)`
0:01:28
Evaluate the following limit: `(lim)_(x-mt0)(sin2x)/(e^x-1)`
0:01:52
IIT JEE LIMITS AND DERIVATIVES Evaluate: `(lim_(n- gt oo)ncos(pi/(4n))sin(pi/(4n))`
0:01:35
`lim_[x- gtpi/4][sec^2x-2]/[tanx-1]`