#19 : Find a String | Hackerrank Python Solutions

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[laxmikantadahal]

def count_substring(string, sub_string):
count=0
for i in range(len(string)):
if
count=count+1

return count

if __name__ == '__main__':
string = input().strip()
sub_string = input().strip()

count = count_substring(string, sub_string)
print(count)

[RajeshR-hmxr]

For I in range(0, ml):
If substring==string[i:i+sl]:
C+=1

[nunnasaicharan]

I have a doubt dear admin.
String : Krishna
Substring : Kri
It is giving the output 1 but the output must be
can you explain this?

[aishwary]

why does it not throw arraylist out of bound exception and passes all test I am iterating to full string ?

count =0
fl = len(string)
sl = len(sub_string)
for i in range(fl):
if string[i:i+sl] == sub_string:
count +=1

return count

[aishwary]

why does this not work ? this fails two test cases out of all

def count_substring(string, sub_string):
count = string.count(sub_string)
return count

if __name__ == '__main__':
string = input().strip()
sub_string = input().strip()

count = count_substring(string, sub_string)
print(count)

[anujpathak]

bhava explain thoda ajun detail madhe karat jaa na please if possible....baaki its very helpfull

[drishtijain]

Tell the solution using string in built function if any,

[sushmamc]

Did not really understand how it works

[TJ-woxt]

explanation not satisfactory, but good approach.