Inverse Laplace Transform of arctan(1/s), Sect 7.4#36

inverse laplace of arctan(1/s),
inverse laplace of tan^-1(1/s),

, inverse laplace transform with completing the square, inverse laplace transform with factoring, inverse laplace transform with derivative,

blackpenredpen

[tommytseng]

god thanks bro, you saved my final exam.

[chadd_robertson]

Great explanation - helped me a lot. Thanks!

[eqwqhvf]

I am addicted to blackpenredpen and watch as many videos as i

[not_vinkami]

That might help you to do ∫[0, ∞](sin(x)/x)dx

[yue]

muchas gracias por el vídeo, fue de gran ayuda.

[donnamach]

You're the best!! Thank you so much!

[glodikanda]

Thank you very much sir for the explication I really appreciated

[jharmley]

Uhm, can I use this technique to others as well?

[cacbon-dioxit]

This is my solution. But it might be wrong.
Note arctan x = x - x³/3 + x⁵/5 - x⁷/7 + ...
Then arctan (1/s) = s^-1 - s^-3/3 + s^-5/5 - s^-7/7 + ...
So L^-1 {arctan (1/s)} = L^-1{s^-1} - L^-1{s^-3/3} + L^-1{s^-5/5} - L^-1{s^-7/7} + ...
= 1 - t²/3! + t⁴/5! - t⁶/7! + ...
= sin(t)/t

[JohnSmith-iufc]

I dont think it's so simple. Pls check again!!

[Pikachu-geti]

where can i watch the explanation video for the statement?

[red-drug-jz]

Do you have a 'Fourier serier'?

[An_art_appreciator]

hi...what is the inverse Laplace transform of e^-1/s?

[ianmii]

The not normalized sinc function!!! :D