Solving the Exponential Equation 2^(3x - 2) + 8^(x - 1) = 0

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Solving the Exponential Equation 2^(3x - 2) + 8^(x - 1) = 0

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Thanks for this video. I always forget to take a step back to see what's going on overall.

nexusnexus

My solution to this is because it is the same binomial, meaning that there is an intersection

10 ⁴x-3 =0 > 40x - 30 = .75 > 0÷0.75 = 0

Or

6x-4 + 8x - 8 = 0

tutopi

Another way I was thinking about when messing around with this was, once you get to 2^(3x-1) + 2^(3x-3) = 0, even if you haven't noticed that both numbers are positive, you might note that the absolute value of both parts of that sum must be the same, because adding them creates a zero, which must mean that the powers must be the same; so 3x - 1 = 3x - 3 which the student will realize is impossible once they subtract 3x from both sides . This was actually an after thought though, and might not be thorough enough.

TinyMaths

Shouldn't there be a way to come up with a formula to compute the weight of the Eiffel Tower to some point from the top? It is 300 meters tall. Say you put in 260 and the formula will give the weight from the top to 260 meters down. So by using the formula twice and subtracting the weight of any slice of the tower could be computed.

Lots of sources call the ET exppnential.

psikeyhackr

This is basic, do more complicated like calculus or college level math, this is so basic

mikaellukasagnusdeianggo

At the last step, wouldn't you rather take log₂ of both sides to get
3x-2 = log₂(5)
and solve from there?

core-nix

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