Applying the Navier-Stokes Equations, part 2 - Lecture 4.7 - Chemical Engineering Fluid Mechanics

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Simplifying conservation of mass and momentum for analysis of flow through a pipe.

[NOTE: Closed captioning is not yet available for this video. Check back soon for updates.]

This video is part of a series of screencast lectures presenting content from an undergraduate-level fluid mechanics course in the Artie McFerrin Department of Chemical Engineering at Texas A&M University (College Station, TX, USA).

The screencasts have been prepared in 720p HD with accompanying closed captioning for enhanced accessibility.

My inspiration for producing this series of videos has been my lifelong personal journey to understand fluid mechanics and explain its beauty to others in a straightforward way. I have received no external support for this project...the effort is purely a labor of love.

I would like to acknowledge Aashish Priye and Jamison Chang for assistance in developing the materials and preparing the captioning.

Please feel free to share any comments or suggestions.

Best wishes,
Victor Ugaz
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>an 11 minute long video on youtube is more valuable than 4 hours of lecture at my uni
really makes you think...

theneonpython
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Thank you! You explain it like you are genuinely amazed that all this stuff works out nicely and you want to let others in on the secret. Appreciated.

giseleroscoe
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Thank you a lot I really needed some slowly explained example. Cheers!

estefaniarnico
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I'm an engineering student from Brazil. I'm grateful for the explanations.

altairfilipinijunior
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Thanks! Much appreciated for explaining this. Keep up the good work

myzas
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Why in a pressure driven flow are we able to neglect gravity? Wouldn't gravity slightly change the magnitudes of the vectors in z (smaller for the bottom half and larger for the top half) due to gravity pulling particles down onto a surface we assumed to have 0 velocity? Or are we assuming that this problem is in a 0 gravity environment so the orientation of the pipe makes no difference. It seems like gravity would almost create a shift of the Vz(r) that was calculated

Wisconsin_Cheese
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amazing video, explained everything. I was confused by what terms need to be cancelled out for a while

ultraslashism
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Hello Victor- Wouldn't it be more appropriate to say that d(vz)/dz = 0 is an outcome of continuity equation (at 3.4 mins), rather than saying that we know in advance v does not change with z?
Then this outcome of the continuity equation i.e. d(vz)/dz =0, is adopted later in momentum equation at 8.43 mins and 9.33 mins for d2(vz)/dz2.

dannychoo
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Thank you. This video was really helpful

dsbupadrasta
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Thanks for explaining. It is very interesting and challenging for me.
I have question. In applying the conservation laws how we got 1/r before the partial derivatives? Sorry if it is too easy

sardorerjigitov
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it is nice everyone should look it &understand the real world

BeleteAssefa
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What are Vr and Vtheta? Is Vtheta angular velocity? What direction are they going in?

lukepapaspyrou
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How is it possible for p to vary with z, if v_z doesn't. I mean, you eliminated ∂v_z/∂z, but kept ∂p/∂z. It doesn't make sense to me (I'm starting to believe that this pressure is not the same pressure that we use in other equations, such as Bernoulli's equation) D;

deyvisonsa
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Very complicated problem for me but the uploader tamed it i must admit

aliasanon
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In the Navier-Stokes how do you derive the cylindrical coordinate form for the laplacian * the velocity vector?

bernardkrasnisky
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Great video. You actually make this exciting. I have a question though; how would this change if this was a gravity driven flow, and not pressure? I simplified it to be rho*g= 0. However, wouldn't that make my entire equation go to zero?

keturahbethel
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stay at home mom stumbled upon this & fascinated. stuff just jumps out at me & it seems obvious. I never took calc & please, please don't think i'm here to talk trash. i have a formula but don't know how to write it out. lol Just have to say, thrilled i found this & curious to see if my entire "formula" continues to be correct. now i know why teachers want you to show your work, lol. Also I cant help but notice & seems obvious ...a lot of Nothing-from Nothing Equals Nothing. I assume all the incorrect formulas are for the process of elimination.

sophiamento
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When velocity varies in r-direction then how we have v subscript r=0????

NadeemAhmed-
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i dont get vz(r) ? how r is another direction and z is another direction?

zee_
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Gravity in the r direction shouldn't be neglected according to my textbook.

adammany