Finding a Limit of a Piecewise Function by Graphing

[JibzCastor]

We need this kind of teacher, I hope you can tutor me. I really don't get whats my prof's teaching right now, she's fast and suddenly moving on the next topic w/out understand the lessons and when I take the test, I know I'm doomed....
I hope she realized that people have different style of learning. Just because someone understands it doesn't mean everyone understand it.

Anyway, thanks for your tutorial! Be safe and God bless! :D

[candymist]

Your voice is nice and really easy to listen to and it makes me feel like less of an idiot for not understanding. Thank you :)

[Catherine-qcws]

May you add more videos about how to improve precise definition of a limit? I very like your videos, and it helps me a lot! Thanks for your sharing!

[LAcrescini]

OMG. You have a very brilliant mind!!!! You helped me a lot. I can't understand my calculus professor that's why I had to look for alternative way to learn, and fortunately it was your videos!!!! =)

[Gobbedlygook]

I never understood how to graph piece wise functions or the problems until I watched your video, thank you so much!

[wworm]

actually lim for x->0 exists here, it's 1 for x->0^- and 3 for x->0^+ cause the function brokes on 0 and it gives 2 different values on the same point, just depending on which side we are closing to the 0.

(sorry if my math-english isnt perfect, i'm not a native speaker)

[essabessa]

Hi, I'm confused when you found the limit as x approaches 0. I understand when looking at the graph that there is a jump so it DNE, but if I were to just plug it into the function without making a graph, (2x+3), how do you know that it isn't 3? Thanks for the great videos!

[shortiiq]

You're such a great teacher. Thank you!

[LadyGuapo]

Thank you. I didn't understand the Piece-wise graph. I can understand my homework.

[aneesm]

Just found this! Thank you so much man, you deserve so much more than just words, but I'm running broke to do otherwise

[ObviousOctopus]

Hey! Awesome video!! These videos totally helped while I was taking calculus. There are a few mistakes in the captions that would really help people out who can't hear! Only a few small things I noticed, such as instead of y-intercept positive 1 it should be y-intercept AT positive 1. Thanks!

[thebluebeyond]

You have made me wanna try these before watching the videos.

[izzystreaks]

I think im going to pass my calc exam D:

[trillfire]

the limit does not exist if the graph brakes. a function cannot have two different values for a limit, the function must be continuous at a certain point in order for the limit to exist. the function x²+1 is continuous at -2 there for the limit of 5 exist

[mrmisspretty]

How do i find calue of k as i was a given a piecewise function of kx square where x is less than or equal to 2 and when x is more than 2. So that the function continuous?

[merylldiola]

Hi! I'd like to know what if the piecewise function has no RHL(no equation if x is greater than the value that the limit approaches) ? Does the limit still exist?

[mahnoorasghar]

great video, thanks!
why doesnt the limit exist at x=0? i mean, the function is defined as 2x+3 for x=0..but not defined as x^2 +1 for x=0....so at x=0, we just have one value of g(x), right? please reply :)

[cristinaespinoza]

at the end.. what if the question was find f(0)? would you put both 1 and 3 as the solution? or dne?

[miramir]

According to our basic calculus professor, never put an equal sign if the limit is DNE(does not exist), because it's not a value

[nascar]

How can you prove lim of 0 algebraically?