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If n is a natural number,then 9^2n-4^2n is always divisible by....
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Real Numbers ,Class 10 Mathematics CBSE NCERT
6^n-5^n=
6^n-5^n=
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1.5.9 Prove by contradiction that if n is a natural number, then n/(n+ 1) is greater than n/(n+2)
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If n is a natural number, then by which numbers 9^2n-4^2n is always divisible
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34. If n is a natural number, then 2(5n + 6n) always ends with(a) 1 (b) 4 (c) 3
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If n is a natural number,then 9^2n-4^2n is always divisible by....
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If n is an even natural number, then `sum_(r=0)^n (-1)^r/(.^nC_r)` equals
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If `n` is a natural number, then `sqrt(n)` is: (a) always a natural number (b) always an irra
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If n is a natural number, then which of the following expression ends in | Class 10 MATH | Doubtnut
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If n is a natural number then how many values of n is possible if cube root of n is greater
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If n is a natural number, then which of the following is not always divisible by 2
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The expression 2^6n - 4^2n , where n is a natural number is always divisible by
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If n is as natural number, using mathematica induction show that: ` n^7-n` is a multiple of 7.
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If n is any natural number, then 4^3n – 1 is not divisible by
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If n is any natural number ,then 6^n -5^n always ends with..Class 10 CBSE Mathematics
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