filmov
tv
If n is a natural number then how many values of n is possible if cube root of n is greater
Показать описание
Gargi Games
Рекомендации по теме
0:03:06
1.5.9 Prove by contradiction that if n is a natural number, then n/(n+ 1) is greater than n/(n+2)
0:06:15
If n is a natural number, then by which numbers 9^2n-4^2n is always divisible
0:00:36
34. If n is a natural number, then 2(5n + 6n) always ends with(a) 1 (b) 4 (c) 3
0:04:04
If n is a natural number,then 9^2n-4^2n is always divisible by....
0:01:33
If n is any natural number then 12^n cannot end with the digit 2 4 8 or 0 #Maths_Term_1_JSK/1
0:02:50
If n is a natural number, then √(n) is (a) always a natural number (b) always a rational number (......
0:01:49
If n be any natural number then by which largest number n^3-n is always divisible
0:01:25
If n is the smallest natural number such that n + 2n + 3n + ...+ 99n is a perfect square, then t....
2:02:37
2022 past paper | MAT livestream 2024
0:03:52
1.4.8 Give two proofs that if n is a natural number, then n^2 + n + 3 is odd. (a) Use two cases.
0:06:05
If n is an even natural number, then `sum_(r=0)^n (-1)^r/(.^nC_r)` equals
0:01:53
If `n` is a natural number, then `sqrt(n)` is: (a) always a natural number (b) always an irra
0:01:59
'If `n`is a natural number and `n=p1x_1\ p2x_2\ p3x_3`, where `p_1,\ p_2,\ p_3`are distinct pri...
0:02:02
If n is a natural number, then which of the following expression ends in | Class 10 MATH | Doubtnut
0:01:57
FILL IN THE BLANK TYPE QUESTIONS If n is a natural number, then the number of consecutive zeros i...
0:01:58
If n is an odd natural number `3^(2n) + 2^(2n)` is always divisible by
0:02:57
If n is a natural number. Then `{:[(2,-1),(3,-2)]^n:}`, is
0:02:32
If n is a natural number then how many values of n is possible if cube root of n is greater
0:04:02
If N, the set of natural numbers is partitionaed into groups `S_(1)={1},S_(2)={2,3},S_(3)
0:02:52
If n is a natural number, then which of the following is not always divisible by 2
0:01:09
The expression 2^6n - 4^2n , where n is a natural number is always divisible by
0:08:55
If n is as natural number, using mathematica induction show that: ` n^7-n` is a multiple of 7.
0:03:08
If n is any natural number, then 4^3n – 1 is not divisible by
0:02:21
If n is a natural number, then (4^(n) -3n -1) is always divisible by- | 12 | MCQ's | MATHS | CH...