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If tan θ = a/b, show that ((a sinθ-b cos θ))/((a sinθ+b cosθ ) )=((a^2-b^2 ))/((a^2+b^2 ) )
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If tan θ = a/b, show that ((a sinθ-b cos θ))/((a sinθ+b cosθ ) )=((a^2-b^2 ))/((a^2+b^2 ) )
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If tan θ = a/b , then ((a sin θ - b cos θ))/((a sin θ+ b cosθ )) =
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if tan theta=a/b, show that (a sin theta+b cos theta)/(a sin theta-b cos theta)=(a²+b²)/(a²-b²)
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If` tan theta = b/a`, then the value of `cos 2theta` is
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