If tan θ = a/b , then ((a sin θ - b cos θ))/((a sin θ+ b cosθ )) =

If tan θ = a/b , then ((a sin θ - b cos θ))/((a sin θ+ b cosθ )) =
a. (〖(a〗^2 〖+ b〗^2))/(〖(a〗^2 〖- b〗^2)) b. (〖(a〗^2 〖- b〗^2))/(〖(a〗^2 〖+ b〗^2)) c. a^2/(〖(a〗^2 〖+ b〗^2)) d. b^2/(〖(a〗^2 〖+ b〗^2))

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Sir esko hamPythagoras theorem lagakar bhi to kar sakte hain kya vah Tarika galat hoga