Uniformly Distributed Load (UDL): Shear Force and Bending Moment Diagram [SFD BMD Problem 4]

In this video we are Going to Learn about How to solve problems on Shear Force diagram [SFD] and Bending Moment Diagram [BMD] for overhanging beam with three Loads. In this problem three loads is acting downward because of that the reaction offered by the supports will be in upward direction. So at point A there will be Ra i.e. reaction at point A
and at point B there is reaction force Rb.

Timecodes
0:00 - Problems on Shear force and Bending Moment Diagram [SFD and BMD] for Uniformly Distributed Load
0:06 - How to Convert Uniformly Distributed Load into Point Load
0:29 - Calculations of Reaction forces for Uniformly Distributed Load
2:16 - Shear force Calculations for Uniformly Distributed Load
6:36 - Bending Moment Calculations for Uniformly Distributed Load

This problem we are going to solve it, in 3 simple steps.
1. Calculate the values of support Reaction.
2. Calculation of Shear force
3. Calculation of Bending Moment

Note: In shear force diagram, whatever the Portion drawn above the reference line, I will show this by positive sign. And the Portion drawn below the reference line, I will show this by negative sign. So here I have completed shear force diagram
Note: In bending moment diagram, whatever the Portion drawn above the reference line, I will show this by positive sign. And the Portion drawn below the reference line, I will show this by negative sign.

You can also watch separate videos for Shear Force and Bending Moment Problems on 4 types of beams -

You can also watch Playlist on Shear Force and Bending Moment Solved Problem

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Faculty - Shubham Kola
From - Maharashtra ( India )

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[md.hasanuzzamanjihad]

Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving

[gabrielatem]

Could you clarify how length x=3.57 become force at maximum point E?

[baiklahtu]

Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?

[VijayVijji-yrlz]

Hlo any one tell me how to get 3.57 answer

[FilmonAron-qxgg]

Thank you so much for the clear explanation!

[strdpraz]

Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye

[gluton]

while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??

[kenken]

Can you also do for moving loads, and triangular loads example? Thank you.

[AnanyaAugustine]

Thank you for the detailed explanation