Operators - CS50 Shorts

preview_player
Показать описание
***

This is CS50, Harvard University's introduction to the intellectual enterprises of computer science and the art of programming.

***

HOW TO SUBSCRIBE

HOW TO TAKE CS50

HOW TO JOIN CS50 COMMUNITIES

HOW TO FOLLOW DAVID J. MALAN

***

CS50 SHOP

***

LICENSE

CC BY-NC-SA 4.0
Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International Public License

David J. Malan
Рекомендации по теме
Комментарии
Автор

No-one comments how caring Doug Lloyd is in his explanations? He is such a joy to listen to!

Maha_s
Автор

Thank you to the teacher as well as to Harvard university...

sudhakarsingh
Автор

Great explanations, better than millions of teachers out there, you can see and feel he cares

jhnarthur
Автор

Might be useful to note that on British keyboards, the vertical bar | is next to left shift

ltflipper
Автор

That's a very good video for beginners! :) Really helps. From a teaching standpoint I would include real world examples for those having trouble getting those truth tables. The hole CS50 course is really well thought out. 👍

maflo
Автор

I don't like reading the comments because you guys confuse me with those smart questions

paulasuzettebravo
Автор

thank you very much for such a great class for me!!!!

MINGWEILI-vqpl
Автор

wondering what is the etymology/origin of calling ! 'bang'? Did it come out in a certain programming circle?

andzrit
Автор

2:36

actually I think you'll find it is 13 divided by 4🤓

xcurrentbreeze
Автор

Why wasn't mentioned in the video about the operators:

++x;
--x;

?

Why x++ is preferred over ++x?

fabiano-co
Автор

Anybode wanna cooperate on Lab 1? It seems we are required to cooparate with classmates, but I'm taking the course online.

Trevor
Автор

It would be nice to make a video (only) of operators for strings.

joostvanderlinden
Автор

if non-zero values evaluate to true, couldn't you get the exact same functionality as a for loop, in a while loop instead?

just have the while loops start with "while (i)", and then at the end of each loop just reduce i by 1

Ausar