Heaviside step function

preview_player
Показать описание
Defines the Heaviside step function and computes its Laplace transform.

Рекомендации по теме
Комментарии
Автор

t' is just a dummy variable, if I have, for example, f(t') = t' it's the same as having f(t) = t, so it doesn't really matter what symbol you use for the argumente, the function, and the Laplace Transform, will be the same.

salesv
Автор

Really well explained ! thank you very much !
The only question I have is, How do you get in the very last end that the laplace transform of T' equals L(T) ?

I mean, how did u get this relationship of T' to T ?

Many thanks

marchlondon
Автор

For the sin function, how can you assume that for t values less than c, the function will be 0?

lasredchris
Автор

For the last two integrals, are the lower bounds supposed to be zero or "c"?

ahyes
Автор

im not sure he actually meant t` turns into t. when we did this problem in class we used a u substitution instead of t`
so your ending should read e^(-s*c)*Laplace{f(u)}
thats how i understood it at least.

NathanSibs
Автор

a pesar de ser latino le entendi a la explicación, lo único restante fue el ejemplo

germanelnica
Автор

OK so I'm a pain in the ass but it's called the Heavieside function, named after the British mathematician Oliver Heavieside - hot heaviside.

_hhk