What's the Shortest International Border in the World?

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A dude actually left a one star Google review of an international border.

duckmeister
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when a kid from Netherlands said his next door neighbor came from the different country, he's not lying.

thibio_x
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How many Toyotas can we fit in that border?

kingsofserbiangameplay
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As a Zimbabwean, I am very happy because of this mention

princem
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"In two-thousand NOW"

I'm stealing that

crazyjaybe
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*No planes?!*

*_Wendover Productions has left the chat_*

BobMcCoy
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3:02
Almost there.
Oh wait, Spain, you forgot a bit.
Spain?
Spain, what about these bits?
*_S P A I N ?_*

literallyabowlofcereal
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Did you know that since 1986, France and Great Britain share a common terrestrial border which is located in the Tunnel that links the 2 countries. I think that's no longer than 40 meters .. that could be even shorter than the one you mentioned in your video !

FredericGaillot
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Canada and mexico

Its 0 miles accros

demkoolduds
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*whips out a notepad and a pencil* The green shaded area is 2 times bigger than the blue shaded area

thegeodudeking
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Could you use bananas for scale? I kept getting confused about the scale

Samtoxie
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4:30 area of a circle is calculated as pi times the radious ^2, so if the radius of the blue area is 1 unit, the radious of the green one is 3
If we define a new area unit that is the radius of blue squared times pi, then the total blue area is 3, and the total green area is 6 (9 - 3). Twice as big

defensivekobra
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Geography Now mentioned this yesterday in his Morocco Video.

TowerGuy
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You and Wendover Productions should do a collaboration :)

vasudevsharma
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Spain: "Hey Britain, you need to return Gibraltar to us."
Morocco: "Ahem!"

thePronto
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The Spanish are playing king of the rock

Karan-pdrz
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About the riddle in the end:
Each of the small semicircles have an area of πd^2/8 and the the whole shape, green and blue, has an area of π9d^2/8. The small semisircles have a combined area of 3πd^2/8. By subtracting the combined area of the shape with the area of the semicircles we get an area of 6πd^2/8 witch is the green one.
So the green area is 2 times larger than the blue one.

Mark-bleg
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2:58 You're turning in to Bill Wurtz here.

AsTaFTheRealOne
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4:31
Assumptions:
1. The compositions of both the blue and green areas form half of a perfect circle
2. Each blue area is half of a perfect circle
3. All blue areas are equal in radius
4. The sum of the blue diameters is equal to the total half circle diameter composed of both the green and blue areas

Solution:
DFN: D - The diameter of one blue circle
DFN: R - The Radius of 1 blue circle
2R = D

The Area of one blue circle:
A_b = (pi*R^2)/2
The Net Area of the blue sections:
(By Assumption no. 3) A_b-net = (3/2)pi R^2

The Area of the green/blue section:
(By Assumption no. 4) A_b/g = [pi (3D/2)^2]/2
(D/2 = R -> A_b/g = pi(3R)^2)/2
IE the area of the total composition is half of the area of a circle, whose radius is defined as half of the total diameter composition (defined as D from each blue section, which there are 3 of).
Specifically:
A_b/g = ([9D^2]/4)(pi/2)
OR
A_b/g = pi (9R^2)/2

Area of the green and blue composite area: 9pi R^2/2
Area of blue area: 3pi R^2/2
Difference between the green and blue area:
A_comp = [9-3] pi R^2/2
A_comp = 6pi R^2/2
A_comp is the area of the green section (we removed the blue areas from the total composite area)

6pi R^2/2 = 2 x 3pi R^2/2
IE
The area of the green section is defined as being twice the area of the total blue section.

The area of the green section is 2 times greater than that of the blue section.

danese
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“Were only half way through the video”
Me: * checks video *
Also me: *oh sht u right*

alchx