Lec-54: Fragmentation of IPv4 Datagram | Identification, Flags and Fragment Offset | Networks

This video explains the concept of Fragmentation of IPv4 Datagram.
When a packet is received at the router, destination address is examined and MTU is determined. If size of the packet is bigger than the MTU, and the 'Do not Fragment (DF)' bit is set to 0 in header, then the packet is fragmented into parts and sent one by one.

0:00 - Introduction
0:27 - Fragmentation
0:59 - Identification bits
1:33 - Flag
3:21 - Fragment Offset
3:47 - Numerical

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[pratham]

Education system needs teachers like you great job 👍💯💯💯

[niteshkushwaha]

Following piece of information is missing in this lecture:
Router uses the following rule to choose the amount of data that will be transmitted in one fragment-

RULE::->
The amount of data sent in one fragment is chosen such that-

It is as large as possible but less than or equal to MTU.
It is a multiple of 8 so that pure decimal value can be obtained for the fragment offset field.

NOTE::->
It is not compulsory for the last fragment to contain the amount of data that is a multiple of 8.
This is because it does not have to decide the fragment offset value for any other fragment.

[sd-nkou]

Why would anyone give this a thumbs down? He did a phenomenal job of explaining these important concepts

[crazorutvikk]

Would not have been able to appear for the exams without your videos. The online lectures is the worst and your lectures were like the Shining light for me. Thank you so much and Much Love !!!!

[prakritigupta]

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[mustaqahmed]

Here the pure data of each datagram should be divisible by 8. You didn't mention that and directly took the number 480 which is divisible. On my question total data was 600 and mtu was 250.Header data was 20. I wrote 230+20. But 230 is not divisible by 8. Hence my answer was wrong. This question carried 15 marks. 🥲

[rigzen_lhadol]

I love your way of teaching sir... U make everything so simple. Thnkew😊

[princejacob]

Got one one "Aaha" moment. Really amazing.

[abishekbabu]

AWSOME EXPLANATION SIR. Clear Shot for all examinations. LOTS OF RESPECT FROM BOTTOM OF MY HEART.

[subhankarhalder]

saved my last minute prep.. thanks sir!

[AsarMd]

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[akshatpareek]

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[parikshiturs]

CN became easier for me because of gr8 teachers like u sir... thanks a lot :)

[Arza]

YOU SAVED MY LIFE!!! BRILLIANT EXPLANATION!! You deserve so much more views man you are a brilliant teacher!! Bauhat Shukria, Love from Pakistan <3 Subscribed!!

[navdeepp]

If link is with MTU 576Bytes instead of 500Bytes, then we should make each fragment packets of 572 bytes (not 576 bytes), because 572-20 = 552 bytes divides by 8 gives integer number. (576-20 = 556 bytes divides by 8 doesn't give integer number)

[mohanam]

Sir pls comparison between IPV4 and IPV6...

[pratheekhebbar]

thank you so much for the wonderfull explanation.finally got the best

[roshanzameer]

You deserve much more subscribers. Even having 1.3M subscribers i can say that you are underrated. You deserve all my respect as a teacher.

[usmanshah]

why total length value exceeds the original limit of datagram i.e 3000 bytes.. As in your case total length comes out to be 3120 bytes instead of 3000 bytes, please elaborate this point.

[vickyprajapat]

Online lectures are worst your videos are very helpful I watch all of your videos to understand and my exam are coming 😶your videos will help me a lot